If 5/9 of a tank can be filled in 2minutes , how many minutes will it take to fill the whole tank?

What is the surface area of a rectangular prism with a length of 16 cm, a width of 8 cm, and a height of 4 cm? (show your work i

11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

Multiply base area * height

= 16 * 8 * 4 = 512 cm^3

6 0

3 years ago

Read 2 more answers

Define Postulate In Geometry ?

MakcuM [25]

To suggest something such as an idea.

4 0

3 years ago

A group of students estimated the length of one minute without reference to a watch or clock, and the times (seconds) are list

Kitty [74]

Answer:

It does not appear that, as a group, the students are reasonably good at estimating one minute.

Step-by-step explanation:

We are given the following data in the question:

75, 88, 51, 73, 49, 31, 69, 74, 72, 59, 72, 81, 99, 101, 73

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1067}{15} = 71.13$

Sum of squares of differences = 4739.733

$S.D = \sqrt{\frac{4739.733}{14}} = 18.39$

Population mean, μ = 60 minutes

Sample mean, $\bar{x}$ = 71.13 minutes

Sample size, n = 15

Alpha, α = 0.10

Sample standard deviation, s = 18.39 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 60\text{ minutes}\\H_A: \mu \neq 60\text{ minutes}$

We use Two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{71.13 - 60}{\frac{18.39}{\sqrt{15}} } = 2.34$

Calculating the p-value from the table, we have,

P-value = 0.034354

Since the p-value is lower than the significance level, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Thus, we conclude that it does not appear that, as a group, the students are reasonably good at estimating one minute.

7 0

3 years ago

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

tekilochka [14]

Answer:

I think Its B

Step-by-step explanation:

7 0

3 years ago

11111111111111111111111

Nat2105 [25]

Answer:

1) Zero based on (-16·t - 2) is t = -1/8 second

2) Zero based on (t - 1) is t = 1 second

Step-by-step explanation:

The given functions representing the height of the beach ball the child throws as a function of time are;

y = (-16·t - 2)·(t - 1) and y = -16·t² + 14·t + 2

We note that (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

Therefore, the function representing the height of the beachball, 'y', is y = (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

The zeros of a function are the values of the variables, 'x', of the function that makes the value of the function, f(x), equal to zero

In the function of the question, we have;

y = (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

The above equation can be written as follows;

y = (-16·t - 2) × (t - 1)

Therefore, 'y' equals zero when either (-16·t - 2) = 0 or (t - 1) = 0

1) The zero based on (-16·t - 2) = 0, is given as follows;

(-16·t - 2) = 0

∴ t = 2/(-16) = -1/8

t = -1/8 second

The zero based on (-16·t - 2) is t = -1/8 second

2) The zero based on (t - 1) = 0, is given as follows;

(t - 1) = 0

∴ t = 1 second

The zero based on (t - 1) is t = 1 second

4 0

3 years ago