Answer:
Length of the volleyball court in drawing = 2 mm
Step-by-step explanation:
8 meter = 8 *1000 = 8000 mm
Scale factor = 1 : 8000
Length of the volleyball court in drawing = x
1 : 8000 :: x : 16000
x = 2 mm
W(2) = 2^2 + 2 = 4 + 2 = 6
u(w(2)) = -x -2 = -6 - 2 = -8
answer: u(w(2)) = -8
So find g(0) and g(3)
G(0) = 0^2 -5(0) +3 = 3
And g(3) = 3^2 - 5(3) +3 = 9 - 15 + 3 = 3 so there is no change in g(x) for that interval.
H(0) = 8(0) + 10 = 10
And h(3) = 8(3) + 10 = 34
So the change in h(x) for that interval is 24.
<span>1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2</span>
Answer:
12.56 (13 if rounded)
Step-by-step explanation:
A=pi x r squared
A=2 squared multiplied by pi
A=4 times pi
plug into calculator should be about 12.56
