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3 years ago

Define Postulate In Geometry ?

Mathematics

1 answer:

MakcuM [25]3 years ago

4 0

To suggest something such as an idea.

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Help pleaseeeeeeeeeeee

lina2011 [118]

Answer:

$\sqrt{54}$ and $\sqrt{120}$

Step-by-step explanation:

If a number 'x' is a perfect square, then $\sqrt{x}$ is rational.

25, 36 and 81 are perfect squares, but 54 and 120 aren't, so the irrational values are $\sqrt{54}$ and $\sqrt{120}$

3 0

3 years ago

Read 2 more answers

Given that f(x) = x^2-3/2

AfilCa [17]

Answer:

368<939`01^9292^91 ibtimes

6 0

3 years ago

Alicia had - $11.00 in her

lana [24]

Answer:

$42

Step-by-step explanation:

It's $42 because 11+44.50 is 54.50 and then you take out 6.25 twice because it's her and one friend to get 42 dollars. Hope this helps!

7 0

2 years ago

What is five times three hundred

spayn [35]

The answer is 1500 I hope this help!

4 0

4 years ago

Enter a recursive rule for the geometric sequence. 6, −18, 54, −162, ...

svlad2 [7]

Answer:

The required recursive formula is:

$a_n=(-3)\times a_{n-1}$

Step-by-step explanation:

We are given a geometric sequence as:

6,-18,54,-162,.....

Clearly after looking at different terms of the sequence we could observe that the sequence is an geometric progression (G.P.) with common ratio= -3 denoted by r.

Let $a_n$ represents the nth term of the sequence.

This means that:

$a_1=6, a_2=-18, a_3=54, a_4=-162,......$

As the common ratio is -3.

so,

$a_1=6\\\\a_2=-18=(-3)\times a_1\\\\a_3=54=(-3)\times a_2\\\\.\\.\\.\\.\\.\\.\\.\\.\\.a_n=(-3)\times a_{n-1}$

Hence, the required recursive formula for the geometric sequence is:

$a_n=(-3)\times a_{n-1}$

5 0

3 years ago