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3 years ago

Find the value of x using segment addition.

Mathematics

1 answer:

kolbaska11 [484]3 years ago

3 0

You combine both 2x-12 and x+2 and 11 which makes the equation

2x-12+x+2= 11

The you get your answer which is

X=7

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Under what circumstances would you file form 1040a? form 1040?

dusya [7]

The 1040 can be used by the individual taxpayer to report all worldwide income from all sources plus take care of all of the ather amounts that you would not be able to enter on the 1040 a tax form.

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3 years ago

Help!!<br><br> which expression is equivalent to (m^5 n /pq^2) ^4

lana66690 [7]

$\text{Use:}\\\\\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{nm}\\\\......................................................\\\\\left(\dfrac{m^5n}{pq^2}\right)^4=\dfrac{(m^5n)^4}{(pq^2)^4}=\dfrac{(m^5)^4n^4}{p^4(q^2)^4}=\dfrac{m^{20}n^4}{p^4q^8}$

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3 years ago

A climber who is 6 feet tall, casts a shadow that is 20 feet tall, at the same time that a tree casts a shadow which is 90 feet

Sergio039 [100]

The tree is 76ft. long

3 0

3 years ago

Aaron works as a bar attendant and receives $11 per hour. On Saturday he works for five hours at normal time and three hours ove

scoundrel [369]

Answer:

so his total pay for Saturday would be $104.50

Step-by-step explanation:

He works 5 hours at $11 per hour which gets a total of 55$

He also works 3 hours of overtime where he gets payed 1.5x pay

11 x 1.5 = 16.5 (10x1.5 = 15 1x1.5 = 1.5)

so he gets $16.5 per hour for 3 hours which = 49.5$

49.5 + 55 = $104.50

5 0

3 years ago

Simplify each only using positive exponents:<br> 2x^-3 • 4x^2<br> 2x^4 • 4x^-3<br> 2x^3y^-3 • 2x

erica [24]

<h2>Answer:</h2>

$\frac{2}{x}$

$\frac{x}{2}$

$\frac{4x^4}{y^3}$

<h2>Step-by-step explanation:</h2>

a. 2x^-3 • 4x^2

To solve this using only positive exponents, follow these steps:

i. Rewrite the expression in a clearer form

2x⁻³ . 4x²

ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.

In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to positive as follows;

$\frac{1}{2x^3} . 4x^2$

iii. We then solve the result as follows;

$\frac{1}{2x^3} . 4x^2$ = $\frac{2}{x}$

Therefore, 2x⁻³ . 4x² = $\frac{2}{x}$

b. 2x^4 • 4x^-3

i. Rewrite as follows;

2x⁴ . 4x⁻³

ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

$2x^4 . \frac{1}{4x^3}$

iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;

$\frac{x}{2}$

Therefore, 2x⁴ . 4x⁻³ = $\frac{x}{2}$

c. 2x^3y^-3 • 2x

i. Rewrite as follows;

2x³y⁻³ . 2x

ii. Change position of terms with negative exponents;

$2x^3.\frac{1}{y^3} .2x$

iii. Now solve;

$\frac{4x^4}{y^3}$

Therefore, 2x³y⁻³ . 2x = $\frac{4x^4}{y^3}$

8 0

3 years ago