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3 years ago

Which system of inequalities is represented by the graph?

Mathematics

1 answer:

Tamiku [17]3 years ago

4 0

The blue line...
(1,2),(3,1)
slope = (1 - 2) / (3 - 1) = -1/2
there is a y int at (0,2.5) or (0,5/2)
it is shaded below the line....and it is a solid line
this inequality is :
y = -1/2x + 5/2
1/2x + y = 5/2
x + 2y = 5
x + 2y < = 5.....this is ur inequality

red line...
(0,4), (1,1)
slope = (1 - 4) / (1 - 0) = -3/1 = -3

there is a y int at (0,4)
it is shaded below the line...and it is a solid line
this inequality is :
y = -3x + 4
3x + y = 4
3x + y < = 4 ...this is ur inequality

summary :
ur 2 inequalities are :
x + 2y < = 5 and 3x + y < = 4

You might be interested in

A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o

balu736 [363]

Answer:

$P(X \ge 1) = 0.509$

$P(X \ge 1) = 0.6807$

Step-by-step explanation:

From the question we are told that

The number of students in the class is N = 20 (This is the population )

The number of student that will cheat is k = 3

The number of students that he is focused on is n = 4

Generally the probability distribution that defines this question is the Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally probability mass function is mathematically represented as

$P(X = x) = \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}$

Here C stands for combination , hence we will be making use of the combination functionality in our calculators

Generally the that he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

Here

$P(X \le 0) = \frac{ ^{3} C_0 * ^{20 - 3} C_{4- 0}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ ^{3} C_0 * ^{17} C_{4}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ 1 * 2380}{ 4845}$

$P(X \le 0) = 0.491$

Hence

$P(X \ge 1) = 1 - 0.491$

$P(X \ge 1) = 0.509$

Generally the that he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

$P(X \ge 1) =1- [ \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]$

Here n = 6

$P(X \ge 1) =1- [ \frac{^{3}C_0 * ^{20 -3}C_{6-0}}{^{20}C_6}]$

$P(X \ge 1) =1- [ \frac{^{3}C_0 * ^{17}C_{6}}{^{20}C_6}]$

$P(X \ge 1) =1- [ \frac{1 * 12376}{38760}]$

$P(X \ge 1) =1- 0.3193$

$P(X \ge 1) = 0.6807$

5 0

3 years ago

I need help On these 8 questions that are blank

Ostrovityanka [42]

Answer:

X = 5

Step-by-step explanation:

3x + 12 + 9x = 72

okay hopefully i can explain so when your doing this combine like terms so

3x + 9x = 12x

12x + 12 = 72

then you would subtract both sides by 12

+12 = subtract x+12=2

- 12 = add x-12=2

there just flipped so in this case i would subtract 12

12x + ( 12-12) = ( 72-12 )

so 12-12 = 0 and 72-12 is equal to 60

12x = 60

the divide on both sides l but leave the x alone so its just 60 divided by 12 wich is 5

so X = 5

hope this helps with ur homework a little btw go back and redo ur other awnsers with this new concept hope it helps

7 0

3 years ago

Help please! Will give brainlist for correct answer with steps. If you’re a troll I will report!

atroni [7]

Answer:

x²-10x+34=0. here u go I'm 12

8 0

2 years ago

Twice the sum of a number and seven is three times the number.

Trava [24]

The equation will be 2x + 7 = 3x

subtract 2x from bothsides, you get 7 = x

so x is equal to 7

EDITED

sorry, i didnt read the sum part, so my answer is considered wrong ahaha

2(x+7) equals 3x

distribute, you get 2x+14=3x

then subtract 2x,

the answer for x is 14

8 0

3 years ago

Read 2 more answers

Find the explicit rule given: -3,1,5,9....

kondor19780726 [428]

I hope this help with your questions let me know if you have more
Have a nice day :)

7 0

3 years ago