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4 years ago

Find the perimeter. Can someone guide me on how to do this?

Mathematics

1 answer:

Eddi Din [679]4 years ago

4 0

Just add all the way around I will start on the left and go to the right
23+5+5+8+ 5+6+23+19= 94

Got the 8 by getting the bottom line which is 19 and subtracting the two top pieces 5&6

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What are two different strategies for finding the product of 472 and 33.

Bad White [126]

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4 0

3 years ago

Jason inherited a piece of land from his great-uncle. Owners in the area claim that there is a 45% chance that the land has oil.

Licemer1 [7]

So,

We are trying to find the compound probability of there BEING oil and the test predicting NO oil.

The percent chance of there actually being oil is 45%. We can convert this into fraction form and simplify it.

45% --> $\frac{45}{100}$

$\frac{45}{100}--\ \textgreater \ \frac{3*3*5}{2*2*5*5}$

$\frac{3*3*5}{2*2*5*5}--\ \textgreater \ \frac{3*3}{2*2*5}$

$\frac{3*3}{2*2*5}--\ \textgreater \ \frac{9}{20}$

That is the simplified fraction form.

The kit has an 80% accuracy rate. Since we are assuming that the land has oil, we need the probability that the kit predicts no oil.

The probability that the kit detects no oil will be the chance that the kit is not accurate, which is 20% (100 - 80 = 20). We can also convert this into fraction form and simplify it.

20% --> $\frac{20}{100}$

$\frac{20}{100}--\ \textgreater \ \frac{2}{10}$

$\frac{2}{10}--\ \textgreater \ \frac{1}{5}$

That is the probability of the kit not being accurate (not predicting any oil).

To find the compound probability of there being oil and the kit not predicting any oil, we simply multiply both fractions together.

$\frac{9}{20}*\frac{1}{5}$

$\frac{9}{20*5}$

$\frac{9}{100}$

So the probability of there BEING oil and the kit predicting NO oil is 9 in 100 chances.

3 0

3 years ago

Read 2 more answers

How to simplify to create an equation

spin [16.1K]

You want to distribute and then combine the like terms, as per order of operations. Start by multiplying the 2 by -n and -3, so you get -2n-6. Then distribute the -7 to the 5 and 2n, so you get -35-14n. Combine your n’s and constants, and get -16n-41

7 0

3 years ago

20.) A=49.23 degrees, c=54.8Solve the right triangle. Express angles in decimal degrees.

vivado [14]

$\begin{gathered} a=41.50 \\ b=35.78 \\ B=40.76\text{ \degree} \\ \end{gathered}$

Explanation

Step 1

a) let

$\begin{gathered} A=49.23\text{ \degree} \\ c=54.8\text{ \degree} \end{gathered}$

b) b value

to find the measure of side b we can use cosine function

$\begin{gathered} cos\theta=\frac{adjacent\text{ side}}{hypotenuse} \\ replace \\ cos\text{ 49.23=}\frac{b}{54.8} \\ b=54.8*cos49.23 \\ b=35.78 \end{gathered}$

c) angle B

to find the measure of Angle B we can use sine function

$\begin{gathered} sin\theta=\frac{opposite\text{ side}}{hypotenuse} \\ replace \\ sin\text{ B=}\frac{35.78}{54.8} \\ sin\text{ B= 0.65}\Rightarrow inverse\text{ function to isolate B} \\ B=\sin^{-1}(0.65) \\ B=40.76 \end{gathered}$

d) side a

$\begin{gathered} sin\theta=\frac{opposite\text{ side}}{hypotenuse} \\ sin\text{ A=}\frac{a}{c}=\frac{\placeholder{⬚}}{\placeholder{⬚}} \\ sin\text{ 49.23=}\frac{a}{54.8} \\ multiply\text{ both sides by 54.8} \\ 54.8s\imaginaryI n\text{49.23=}\frac{a}{54.8}*54.8 \\ 41.50=a \end{gathered}$

so, the answer is

$\begin{gathered} a=41.50 \\ b=35.78 \\ B=40.76\text{ \degree} \\ \end{gathered}$

I hope this helps you

7 0

1 year ago

HELP ME ! What is the value of X

Harlamova29_29 [7]

Answer:

I think it would be 7 dnejeias

4 0

3 years ago