A student measures the volume of a liquid in a graduated cylinder of 250 mL capacity, and finds the volume of the liquid to be 2
1 answer:
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Answer: 0.4375 mols of solute
Explanation:
The problem is asking for the amount of solute. We are given the value of molarity. The molarity is 0.25M. We know that molarity is . Since we are given the liters of solution is 1.75, we can use those values to solve for mols of solute.
[multiply both sides by 1.75 L]
There are 0.4375 mols of solute.
The FORMULA for the limiting reagent is .
4.27 grams of reactant remains after the reaction is complete.
<h3>What is a limiting reagent?</h3>The limiting reagent is the reactant that is completely used up in a reaction and thus determines when the reaction stops.
Given data:
Mass of sulfuric acid = 41.0 grams
Molar mass of sulfuric acid = 98.08 g/mol
Mass of zinc hydroxide = 36.5 grams
Molar mass of zinc hydroxide = 99.424 g/mol
Step 1:moles sulfuric acid = mass sulfuric acid / molar mass sulfuric acid
moles sulfuric acid = 41.0 grams / 98.08 g/mol
moles sulfuric acid = 0.41 moles
Step 2: moles of zinc hydroxide
moles zinc hydroxide = 36.5 grams / 99.424 g/mol
moles zinc hydroxide =0.367 moles
Step 3: Calculate limiting reactant
zinc hydroxide is the limiting reactant. It will completely be consumed.
There will remain 0.41 moles - 0.367 moles = 0.043 moles
This is 0.043 moles x 99.424 g/mol
= 4.27 grams
Learn more about the limiting reagent here:
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