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3 years ago

Please don't give me the wrong answers! can I have it as soon as possible? (Thank you)

Mathematics

1 answer:

Semenov [28]3 years ago

8 0

1- there are 10 sections
2- 2/10 &1/5
3 1/5=w/200
4- 5w=200. 200/5= 40. 40 wins

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Anyone know this one?

9966 [12]

Answer:

(-3, 5), (1, 4), (-2, 3), and (0, 2).

Step-by-step explanation:

When a function is inverted, the x-values become y-values, and the y-values become x-values.

The ordered pairs for the function are (5, -3), (4, 1), (3, -2), and (2, 0).

After inversion, the ordered pairs will be (-3, 5), (1, 4), (-2, 3), and (0, 2).

Hope this helps!

7 0

3 years ago

What is the answer for -4x+4y=12 3x-4y=-18

Liula [17]

Use elimination.

-x = -6
X = 6

-4 (6) + 4y = 12
Y = 9

(X,y)

(6,9) is the solution

6 0

4 years ago

If g(x) = x+1/ x-2 and h (x) =4 - x , what is the value of ( g*h) (-3)?

Lapatulllka [165]

Answer:

g (h (x) ) = 5/8

Step-by-step explanation:

We are given the following two functions and we are to find the value of $g ( h ( - 3 ) )$ :

$g ( x ) = \frac { x + 1 } { x + 2 }$

$h ( x ) = 4 - x$

Firstly, we need to find the function :

$g ( h ( x ) ) = \frac { ( 4 - x + 1 ) } { ( 4 - x - 2 ) } = \frac { 5 - x } { 2 - x }$

Now substituting the value $x=-3$ in it:

$g ( h ( x ) ) = \frac { 5 - (-3) } { 2 - (-3) }$

g (h (x) ) = 5/8

5 0

3 years ago

Hurry Please! :)

Sladkaya [172]

Area = b*h and in some cases * 2 so you need to do this, 64*52 + 40*28= 4448 yd2

8 0

3 years ago

Read 2 more answers

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Bogdan [553]

The sum of the inner angles of a polygon with n sides is $180(n-2)$

Since your polygon has 6 sides, the sum of its inner angles has to be

$180(6-2) = 180 \cdot 4 = 720$

On the other hand, the sum of its inner angles is

$75+132+113+108+160+x = 588+x$

And it has to be 720, so we have

$588+x=720 \iff x = 720-588 = 132$

7 0

4 years ago