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3 years ago

Help with number 15 please

Mathematics

2 answers:

Vladimir79 [104]3 years ago

6 0

Answer: B

Step-by-step explanation:

You have two points, use the tilt formula (y2-y1)/(x2-x1)=m. The resultad is -3. And use the straight line formula y-y1=m(x-x1).

In this case, use the first point (1,2)

y-2=-3(x-1)

y-2=-3x+3

y=-3x+5

FinnZ [79.3K]3 years ago

5 0

Answer:

It's B

Step-by-step explanation:

y=mx+b

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Some red, white, and blue candies were placed in a bowl. Some contain nute,

Ganezh [65]

Answer:

Answer:

Option B: 60%

Step-by-step explanation:

The number of blue candies with nuts = 20

The number of blue candies without nuts = 30

The total number of blue candies = 20 + 30 = 50

As the chosen candy is blue, the probability that is does not contain any nuts will be = (The number of blue candies without nuts)/(Total number of blue candies)

So, the probability = 30/50 = 0.6 *100% = 60%

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2 years ago

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The length of a rectangle is x times the square root of 100. The width is one-half y more than three-halves x. Given that the ar

dimulka [17.4K]

Answer:

$15x^2+5xy-125=0$

Step-by-step explanation:

We are give the following in the question:

Dimensions of rectangle:

Length , l =

$l = x\sqrt{100} = 10x$

Width of rectangle, w =

$w = \dfrac{y}{2} +\dfrac{3x}{2}$

Area of rectangle = 125 square cm.

Area of rectangle =

$A =l\times w$

Putting values, we get,

$125 = 10x\times (\dfrac{y}{2}+\dfrac{3x}{2})\\\\125 = 5xy+15x^2\\15x^2+5xy-125=0$

is the required equation.

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2 years ago

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Help Me Figure Out With This Question Please

adoni [48]

Answer:

Step-by-step explanation:

Since you know the angle is a right angle, you can say that the two equations equal 90. A right angle is 90 degrees

3x+40+4x-6=90

Then Simplify

7x+34=90

Then Subtract:

7x=56

Then Divide:

x= 8

After, plug x into the angle equations

1. 3(8)+40= 64

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2 years ago

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How do you integrate arctan(x dx? i think that if you simplify the integral you get:?

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$\displaystyle\int\arctan x\,\mathrm dx=uv-\int v\,\mathrm du$
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For the remaining integral, setting $y=1+x^2$ gives $\dfrac{\mathrm dy}2=x\,\mathrm dx$ , so

$\displaystyle\int\frac x{1+x^2}\,\mathrm dx=\frac12\int\frac{\mathrm dy}y=\frac12\ln|y|+C=\frac12\ln(1+x^2)+C$

Putting everything together, you end up with

$\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\frac12\ln(1+x^2)+C$

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2 years ago

I need the RIGHT answer to this please. :)

KATRIN_1 [288]

A is the answer. It has no repeating x points buy it repeats on the y coordinate, which is okay. The answer is A just to say it again.

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2 years ago

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