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Alex Ar [27]
2 years ago
14

THE COFFICENT OF y in term -y /3 is

Mathematics
2 answers:
Burka [1]2 years ago
6 0

Answer:

-1/3

Step-by-step explanation:

Delvig [45]2 years ago
3 0

Answer:

-1/3

Step-by-step explanation:

hope it helps thanks

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a. The amount that is saved at the expiration of the 5 year period is $22,769.20¢

b. The amount of interest is $2,769.20¢

Step-by-step explanation:

Since the amount that is deposited every year for a period of five years is $4,000 and the rate of the interest is 6.5%. We can always calculate the amount that is saved at the expiration of the five years.

    We will first state the formula for calculating the future value of annuity:-

      Future value of annuity =

                      P[\frac{(1 + r)^{t}-1 }{r}]

   Where P is the amount deposited per year.

   r is the rate of interest

   t is the time or period

 

    and in this case, the actual value of P = $4,000

      rate of interest, r is 6.5% = 0.065

      time, t is 5 years.

   Substituting e, we have:

   Fv of annuity =

                          4,000[\frac{(1 + 0.065)^{5}-1 }{0.065 }]

   = 4,000 × [((1.065)^5)- 1/0.065]

 = 4,000 × [(1.37 - 1)/0.065]

 = 4,000 × (0.37/0.065)

 = 4,000 × 5.6923

 = $22,769.20¢

a. Therefore the amount that is saved at the end of the five (5) years is $22,769.20¢

b. To find the interest, we will calculate the amount of deposit made during the period of five years and subtract the sum from the current amount that is saved ($22,769.29¢).

  Since I deposited 4,000 every year for five years, the total amount of deposit I made at the period =

       4,000 × 5 = $20,000

  The amount of interest is then = $22,769.20¢ - $20,000 = $2,769.20¢

3 0
3 years ago
A scientist is studying the population growth rates of two different species of rats in the same laboratory conditions. The popu
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Since, population of species A is represented by : P=2^{x} +19

Let us find the population of species A, at the end of week 1:

i.e., x = 1

i.e., P(1)=2^{1} +19

i.e., P(1)=2 +19

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Also, since population of species B is represented by : P=3^{x} +18

Let us find the population of species B, at the end of week 1:

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Thus, at the end of 1 week, species A and species B will have the same population.

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=========
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Where’s the graph or whatever???
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