I cannot found the exercise anywhere, so I will just explain how the toxin works.
A toxin is a toxic substance made by a living organism such as a bacterium, a fungus, a plant or an animal.
Labil toxins are toxins which are by easily degraded. among these toxins, there is the toxin of Escherichia coli and the cholera toxin of <span>Vibrio cholerea.
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The intracellular target of cholera toxin is adenylate cyclase, one of the most important eukaryotic cell regulatory systems. This enzyme is involved in the conversion of ATP into a cyclic AMP (cAMP), a crucial intracellular messenger in a wide variety of cellular processes.
Cholera toxin catalyzes the transfer of ADP-ribose from NAD (Nicotinamide Adenine Dinucleotide) to a specific arginine residue of the Gsa protein, resulting in the activation of adenylate cyclase and consequently the increase of the intracellular level cAMP. AMPc activates a cAMP-dependent protein kinase, which leads to phosphorylation of the protein, modification of ion transport and finally diarrhea.
Answer:
Explanation:
We are asked to find how much of a 40 gram sample remains after 12 years.
Iron-55 has a half-life of 3 years. Therefore, after 12 years, 4 half-lives have been completed.
- 12 years/3 years = 4 half-lives
Every time a half-life is completed, half of the sample's mass decays. Remember we start with a 40 gram sample.
- 1 half- life: 40 g / 2 = 20 g
- 2 half-lives: 20 g / 2= 10 g
- 3 half-lives: 10 g / 2 = 5 g
- 4 half-lives: 5 g / 2 = 2.5 g
There is also a formula that can be used to solve this problem.
Where A₀ is the initial amount, t is the time, and hl is the half-life.
We know 40 grams is the inital amount, 12 years is the time, and 3 years is the halflife.
After 12 years, <u>2.5 grams </u> of Iron-55 will remain.
ANSWER:
The answer would be lead ores
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