Two hydrogen isotopes combine to form a helium atom and a great deal of energy. What process is being described?
1 answer:
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The <span>energy of the photon emitted when the electron in a hydrogen atom drops from energy level E5 to energy level E2 is 2.85eV
Now, the energy of the ground state is -13.6 eV.
</span>the energy of the first state (n = 1) is -3.39 eV.
the energy of the fifth state is -0.54 eV.
Now, When an electron drops from higher to lower state, then energy difference is same as the energy of the photon emitted, is
= E5 - E2
= -0.54 eV -(-3.39 eV)
= 2.85 eV
Now, the energy of the ground state is -13.6 eV.
</span>the energy of the first state (n = 1) is -3.39 eV.
the energy of the fifth state is -0.54 eV.
Now, When an electron drops from higher to lower state, then energy difference is same as the energy of the photon emitted, is
= E5 - E2
= -0.54 eV -(-3.39 eV)
= 2.85 eV