Question

What is the value stored at x, given the statements:

Answer 1

Answer:

B. 0

Explanation:

The computation happens in the following sequence:

1) The operands 4.5 and 6.4 are added : 4.5+6.4 = 10.9

2) When this value is cast to int datatype, it becomes 10

3) 3/10 = 0.3

4) x in a variable of type int. So when a value of 0.3 is assigned to x, it is stored as 0.

If we now display the value of x using printf or cout statement, we should expect to see 0 as the value printed on the console.