Answer:
The correct option is:
h = 1, k = 16
Step-by-step explanation:
y=4x^2-8x+20 =0
It is a quadratic formula in standard form:
ax^2+bx+c
where a = 4 , b = -8 and c=20
The vertex form is:
a(x − h)2 + k = 0
h is the axis of symmetry and (h,k) is the vertex.
Calculate h according to the following formula:
h = -b/2a
h= -(-8)/2(4)
h = 8/8
h = 1
Substitute k for y and insert the value of h for x in the standard form:
ax^2+bx+c
k = 4(1)^2+(-8)(1)+20
k = 4-8+20
k=-4+20
k = 16
Thus the correct option is h=1, k=16....
the first one ((x+8, y+2), r x-axis)
9514 1404 393
Answer:
- 6x +y = -6
- 6x -y = 8
- 5x +y = 13
Step-by-step explanation:
To rewrite these equations from point-slope form to standard form, you can do the following:
- eliminate parentheses
- subtract the x-term
- subtract the constant on the left
- if the coefficient of x is negative, multiply by -1
Of course, any operation you do must be done <em>to both sides of the equation</em>.
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1. y -6 = -6(x +2)
y -6 = -6x -12 . . . . . eliminate parentheses
6x +y -6 = -12 . . . . . add 6x
6x +y = -6 . . . . . . . . add 6
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2. y +2 = 6(x -1)
y +2 = 6x -6
-6x +y +2 = -6
-6x +y = -8
6x -y = 8 . . . . . . . . multiply by -1
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3. y -3 = -5(x -2)
y -3 = -5x +10
5x +y -3 = 10
5x +y = 13
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<em>Additional comment</em>
The "standard form" of a linear equation is ax+by=c for integers a, b, c. The leading coefficient (generally, 'a') should be positive, and all coefficients should be mutually prime (have no common factors). That is why we multiply by -1 in problem 2.
Answer:
If you was born in 1946 you would be twenty years old in:
1946+20
1966
Step-by-step explanation:
1)The given equations are:
x − 2y = 6 ...(i)
3x − 6y = 0 ...(ii)
Putting x = 0 in equation (i) we get
=> 0 - 2y = 6
=> y = -3
x = 0, y = -3
Putting y = 0 in equation (i) we get
⇒x-2×0=6
⇒x=6
x = 6, y = 0
Use the following table to draw the graph
x 0 6
y -3 0
Plotting the two points A(0, -3) and B(6,0) equaion (1) can be drawn
Graph of the equation ..(ii)
3x - 6y = 0 ...(ii)
Putting x = 0 in equation (ii) we get
⇒3×0-6y=0
=> y = 0
x = 0, y = 0
Putting x = 2 in equation (2) we get
⇒3×2-6y=0
=> y = 1
x = 2, y = 1
Use the following table to draw the graph.
x 0 2
y 0 1
Draw the graph by plotting the two points O(0,0) and D(2,1) from table
We see that the two lines are parallel, so they won’t intersect
Hence there is no solution
2)
