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DiKsa [7]
2 years ago
5

Is anyone good at geometry if so can someone help me please ? NO LINKS PLEASE

Mathematics
2 answers:
klasskru [66]2 years ago
8 0

Answer:

question one is D I think

motikmotik2 years ago
5 0

Answer:

D

Step-by-step explanation:

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Tenth place is the answer!! :))
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43. ALGEBRA Assume that your current
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Answer:

10582

Step-by-step explanation:

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What number nearest to 100,000 is exactly divisible by 2, 3, 4, 5, 6 and 7?
navik [9.2K]
First find the numbers with the factors of:
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find the minum
if something has a factor of 6 then it also has a factor of 3 and 2 so just multiply by  the lcm of all of them which is found by
2=2
3=3
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4 0
3 years ago
Tell whether the given value is a solution of the inequality.<br><br> a/6 &gt; -4; a = -18
balandron [24]

First we simplify the inequality

1. <em>multiply 6 by the other side of the inequality (-4) </em>

Now we have ...

a > -24

Anything that can be a solution to the inequality <u>must be greater than -24</u>

-18 is greater than -24

This means that, YES! a = -18 IS a solution to the inequality

3 0
2 years ago
9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?
SSSSS [86.1K]

Answer:

Part 4) r=84\ units

Part 9) sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) sin(\theta)=-\frac{9\sqrt{202}}{202}

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

C=2\pi r

using proportion

\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}

simplify

\frac{r}{180^o}=\frac{56}{120^o}

solve for r

r=\frac{56}{120^o}(180^o)

r=84\ units

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

cos^2(\theta)+sin^2(\theta)=1

we have

cos(\theta)=-\frac{2}{3}

substitute the given value

(-\frac{2}{3})^2+sin^2(\theta)=1

\frac{4}{9}+sin^2(\theta)=1

sin^2(\theta)=1-\frac{4}{9}

sin^2(\theta)=\frac{5}{9}

square root both sides

sin(\theta)=\pm\frac{\sqrt{5}}{3}

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?    

see the attached figure to better understand the problem

In the right triangle ABC of the figure

sin(\theta)=\frac{BC}{AC}

Find the length side AC applying the Pythagorean Theorem

AC^2=AB^2+BC^2

substitute the given values

AC^2=11^2+9^2

AC^2=202

AC=\sqrt{202}\ units

so

sin(\theta)=\frac{9}{\sqrt{202}}

simplify

sin(\theta)=\frac{9\sqrt{202}}{202}

Remember that      

The point (11,-9) lies in Quadrant IV

then      

The value of sin(∅) is negative

therefore

sin(\theta)=-\frac{9\sqrt{202}}{202}

5 0
3 years ago
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