Since a stop sign is an octagon it has eight sides. So the perimeter will be:
p=8x, p=perimeter and x=side length. We are told that the perimeter is equal to:
16x^2-80x so we can say:
16x^2-80x=8x subtract 8x from both sides
16x^2-88x=0 factor out 8x
8x(2x-11), since we know x>0
x=11/2
x=5.5 units
To find the number of even factors, we can multiply the number of odd factors by the power of 2 (not the power of 2 + 1!!!). For 540, we have (3 + 1)(1 + 1)(2) = 16 even factors.
No solutions, I don’t think there’re any solutions
Answer:
sin70°
Step-by-step explanation:
Given sin110° where 110° is an obtuse angle in the second quadrant.
The related acute angle in the first quadrant is 180° - 110° = 70°
Thus
sin110° = sin70°
