Please use " ^ " to denote exponentiation: <span>f(x) = 4x^2 + 2x -5. To find the vertex form of this equation, complete the square:
f(x) = 4x^2 + 2x - 5
= 4(x^2 + (2/4)x) - 5
= 4(x^2 + (1/2)x ) -5
= 4(x^2 + (1/2)x + 1/16 ) - 4/16 - 5
= 4(x+1/4) - 21/4 <= in vertex form
Here h= -1/4 and k = -21/4. The vertex is at (-1/4, -21/4)</span>
Answer:
{12,2}
Step-by-step explanation:
From the given graph it is clear that the initial point of the vector is (-5,0) and the terminal point (7,2).
If initial point of a vector is
and terminal point is
, then

Using this formula, we get



Using braces, we get

Therefore, the required vector is {12,2}.
X - the unit
3x; 4x; 5x - the lengths of the sides
3x + 4x + 5x = 30
12x = 30 |:12
x = 2.5
3x = 3 · 2.5 = 7.5 cm
4x = 4 · 2.5 = 10 cm
5x = 5 · 2.5 = 12.5 cm