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Fiesta28 [93]
3 years ago
13

Yun is curious what proportion of users will click an advertisement that appears on his website. He takes a

Mathematics
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

Step-by-step explanation:

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Write the quadratic function in vertex form: f(x) = 4x2 + 2x -5
Andrei [34K]
Please use " ^ " to denote exponentiation:  <span>f(x) = 4x^2 + 2x -5.  To find the vertex form of this equation, complete the square:

f(x) = 4x^2 + 2x                                           - 5
      = 4(x^2 + (2/4)x)                                         - 5
      =  4(x^2 + (1/2)x )                                  -5
      = 4(x^2 + (1/2)x + 1/16  ) - 4/16 - 5
      = 4(x+1/4) - 21/4    <= in vertex form

Here h= -1/4 and k = -21/4.  The vertex is at (-1/4, -21/4)</span>
3 0
3 years ago
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Jus number 5 i need help to evaluating it
solong [7]
I hope this helps you

6 0
3 years ago
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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B80%20%7D%20%20%5Cdiv%204" id="TexFormula1" title=" \sqrt{80 } \div 4" alt=" \sqr
xeze [42]
I think root 5 or 2.236.
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3 years ago
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Equation editor does not include the grouping symbols “&lt;“ and “&gt;” that are necessary for writing a vector in component for
Scilla [17]

Answer:

{12,2}

Step-by-step explanation:

From the given graph it is clear that the initial point of the vector is (-5,0) and the terminal point (7,2).

If initial point of a vector is (x_1,y_1) and terminal point is (x_2,y_2), then

\overrightarrow{v}=(x_2-x_1)i+(y_2-y_1)j

Using this formula, we get

\overrightarrow{v}=(7-(-5))i+(2-0)j

\overrightarrow{v}=12i+2j

\overrightarrow{v}=

Using braces, we get

\overrightarrow{v}=\{12,2\}

Therefore, the required vector is {12,2}.

4 0
3 years ago
The sides of a traingle are in the ratio 3:4:5. what is the length of each sdie of the traingle is 30 cm
liraira [26]
X - the unit
3x; 4x; 5x - the lengths of the sides
3x + 4x + 5x = 30
12x = 30   |:12
x = 2.5
3x = 3 · 2.5 = 7.5 cm
4x = 4 · 2.5 = 10 cm
5x = 5 · 2.5 = 12.5 cm

8 0
4 years ago
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