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Dmitry [639]
4 years ago
7

What is the quotient of -5/7 ÷ 2/35​

Mathematics
1 answer:
Alex17521 [72]4 years ago
6 0

Answer:12.5

Step-by-step explanation:there you go

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In an university, out of 100 students 15 offered Mathematics only;
SVETLANKA909090 [29]
I do not understand what you want me to solve.

4 0
4 years ago
Which property is illustrated? x+y=x+y
Sholpan [36]

Answer:

commutative property of addition

Step-by-step explanation:

commutative property of addition  "a + b = b + a"

7 0
3 years ago
Reflect A(29,-32) across the x-axis. *
Phantasy [73]

The coordinate (20, -32), the reflection of the coordinate over the x-axis is (20, 32)

<h3>Reflection of coordinates</h3>

If a coordinate (x, y) is reflected across the x-axis, the resulting coordinate after reflection is (x,-y)

Note that the y-ccordinate is negated after the reflection.

Given the coordinate (20, -32), the reflection of the coordinate over the x-axis is (20, 32)

Learn  more on reflection here: brainly.com/question/26642069

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4 0
2 years ago
For which function is the average rate of change over the interval 1 &lt; x &lt; 5 greater than the average rate of change over
Rainbow [258]

Answer:

We do not have the function g(x), but this can be solved in a trivial way.

The average rate of change in a interval is the slope over that interval, so the average rate of change of g(x) in the interval 1 < x < 5 is

p = (g(x2) - g(x1))/(x2 - x1) where x2 > x1

p = (g(5) - g(1))/(5 - 1) = (g(5) - g(1))/4

Now, suppose that i have the new equation h(x) = g(x) + x

the rate of change of this function, the average rate of change in the interval will be:

p' = (h(5) - h(1))/(5 - 1) = (g(5) + 5 - g(1) - 1)/4 = (g(5) - g(1))/4 + 4/4 = p +1

so p' > p

and the average rate of change of h(x) is bigger than the one of g(x) in the interval 1< x < 5

5 0
3 years ago
Read 2 more answers
Solve the system by either the addition method or the substitution method.
GalinKa [24]

Answer:x = - 5

y = 2

Step-by-step explanation:

The given system of simultaneous equations is expressed as

x + 3y = 1 - - - - - - - - - - - - - -1

4x + 4y = -12 - - - - - - - - - - - 2

We want to eliminate x. Multiplying equation 1 by 4 and equation 2 by 1, it becomes

4x + 12y = 4

4x + 4y = - 12

Subtracting the second equation from the first equation, it becomes

8y = 16

y = 16/8 = 2

Substituting y = 2 into equation 1, it becomes

x + 3 × 2 = 1

x + 6 = 1

x = 1 - 6 = - 5

6 0
3 years ago
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