For this case, the area is given by:
A = x * (200-2x)
Rewriting:
A = 200x-2x ^ 2
Deriving the expression we have:
A '= 200-4x
Equaling zero we have:
200-4x = 0
We clear x:
4x = 200
x = 200/4
x = 50 feet
Then, the maximum area is:
A (50) = 50 * (200-2 * 50)
A (50) = 5000 feet ^ 2
Answer:
the maximum possible area that can be enclosed with his 200ft of fencing is:
A (50) = 5000 feet ^ 2
If it was reflected over the x-axis it would become (4,-3).
The correct answer is 10/9 or 1.1. Hope this helps.
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Answer:
F. x ≤ -5
Step-by-step explanation:
Translating the diagram to more conventional symbols, we have ...
4x +12 ≤ -8
4x ≤ -20 . . . . . . . subtract 12 from both sides
x ≤ -5 . . . . . . . . . divide both sides by 5
