Recall that zeroes can be transformed into factors by subtracting them from x. This gives us the following factors:
(x - 1)(x + 3)(x - 4)
Now, if you multiply the first two factors together, you get the following:
(x² + 2x - 3)
Multiply that by the last factor, (x - 4), and you get this:
(x³ + 2x² - 3x - 4x² - 8x + 12)
This can be simplified:
(x³ - 2x² - 11x + 12)
And there's your final answer. Hope this helped!
Answer:
Recursive:

Explicit:

And the 20th term is 225.
Step-by-step explanation:
We have the sequence:
35, 45, 55, 65.
Notice that each subsequent term is 10 more than the previous term.
Therefore, our common difference is (+)10.
Recursive Rule:
The standard format for the recursive rule is:

Where a is the initial term and d is the common difference.
From our sequence, we know that a the initial term is 35.
And as determined, our common difference d is 10.
Substitute. Hence, our recursive rule is:

Explicit Rule:
The standard format for the explicit rule is:

Where a is the initial term and d is the common difference. So, let’s substitute 35 for a and 10 for d. Hence, our explicit formula is:

Now, let’s find the 20th term. We will utilize the explicit rule since the recursive rule can get tedious. Substitute 20 for n because we would like to 20th term. Thus:

Evaluate:

Hence, the 20th term is 225.
An equation has infinitely many solutions if it can be manipulated all the way to an identity (i.e. an equality where the right and left hand side are the same). We have:
A) 
which is impossible
B) 
which is an equality
C) 
which has a unique solution
D) 
which has a unique solution
(2) (2+5) = 14
2•2= 4
2•5= 10
4+10= 14
Compare the slopes of the 4 equations, which is the number in the term with "x". The slope with highest absolute value is the steepest. Positive slope means the function is ascending left to right, negative slope means it is descending left to right. If you only care that it is the steepest, regardless of whether it is ascending or descending, then the answer is (D).