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Dennis_Churaev [7]
3 years ago
5

What term can you add to 5/6x-4 to make it equivalent to 1/2x-4?

Mathematics
2 answers:
QveST [7]3 years ago
7 0
X=-6 hope this helps

polet [3.4K]3 years ago
3 0
\dfrac{1}{2}x- 4 - (\dfrac{5}{6} x - 4 )

=   \dfrac{1}{2}x- 4 - \dfrac{5}{6} x + 4

=   \dfrac{1}{2}x - \dfrac{5}{6} x

=   \dfrac{3}{6}x - \dfrac{5}{6} x

=   -\dfrac{2}{6}x

= -\dfrac{1}{3}x

------------------------------------------------------
Answer : - 1/3 x 
------------------------------------------------------

To check:
\dfrac{5}{6}x  - 4  + (- \dfrac{1}{3}x ) =  \dfrac{5}{6}x- \dfrac{1}{3}x-4= \dfrac{5}{6}x- \dfrac{2}{6}x-4 = \dfrac{3}{6}x-4  = \dfrac{1}{2}x-4
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1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t
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1)\text{   }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

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To get the equation, we will use the equation of half-life:

\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

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\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}

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Paul has 6 teaspoons of salt. The ratio of teaspoons to tablespoons is 3:1. How many tablespoons of salt does Paul have?
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