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3 years ago

Plz helpppp I don’t GET THIS

Mathematics

2 answers:

Liono4ka [1.6K]3 years ago

6 0

First you have to find 1/3 of the marbles. That means in the twelve marvels she has, there are three even groups. Divide twelve by three and you get four. So if each group is four, it is simple from here on out. If she started out with twelve and she lost 1/3 of them(4) it would be 12-4. You know this because lost is another for for subtract. 12-4=8. She has 8 marbles left.

Neporo4naja [7]3 years ago

4 0

Answer: Jacqueline has 8 marbles left.

Step-by-step explanation: Its pretty much just asking you how much marbles she has left if she lost 1/3. So you would find 1/3 of 12 which is 4(this is how much marbles she lost but you are trying to figure out how much she has left). So she started with 12, she lost 4, so 12-4 = 8. *To find 1/3 of 12 you can make boxes and demonstrate/shade 1/3 of 12 or you can just do 1/3 and 12/1 cross simplify which would be divided 3 by 3 and divided 12 by 3 so you would get 1/1 and 4/1 which when multiplied would be 4/1 which=4. Hope this helped!

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Three assembly lines are used to produce a certain component for an airliner. To examine the production rate, a random

Katyanochek1 [597]

Answer:

a) Null hypothesis: $\mu_A =\mu_B =\mu C$

Alternative hypothesis: $\mu_i \neq \mu_j, i,j=A,B,C$

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2 =20.5$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2 =12.333$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2 =8.16667$

And we have this property

$SST=SS_{between}+SS_{within}$

The degrees of freedom for the numerator on this case is given by $df_{num}=df_{within}=k-1=3-1=2$ where k =3 represent the number of groups.

The degrees of freedom for the denominator on this case is given by $df_{den}=df_{between}=N-K=3*6-3=15$ .

And the total degrees of freedom would be $df=N-1=3*6 -1 =15$

The mean squares between groups are given by:

$MS_{between}= \frac{SS_{between}}{k-1}= \frac{12.333}{2}=6.166$

And the mean squares within are:

$MS_{within}= \frac{SS_{within}}{N-k}= \frac{8.1667}{15}=0.544$

And the F statistic is given by:

$F = \frac{MS_{betw}}{MS_{with}}= \frac{6.166}{0.544}= 11.326$

And the p value is given by:

$p_v= P(F_{2,15} >11.326) = 0.00105$

So then since the p value is lower then the significance level we have enough evidence to reject the null hypothesis and we conclude that we have at least on mean different between the 3 groups.

b) $(\bar X_B -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_B}{n_B} +\frac{s^2_C}{n_C}}$

The degrees of freedom are given by:

$df = n_B +n_C -2= 6+6-2=10$

The confidence level is 99% so then $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ and the critical value would be: $t_{\alpha/2}=3.169$

The confidence interval would be given by:

$(43.333 -41.5) - 3.169 \sqrt{\frac{0.6667}{6} +\frac{0.7}{6}}= 0.321$

$(43.333 -41.5) + 3.169 \sqrt{\frac{0.6667}{6} +\frac{0.7}{6}}=3.345$

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Part a

Null hypothesis: $\mu_A =\mu_B =\mu C$

Alternative hypothesis: $\mu_i \neq \mu_j, i,j=A,B,C$

If we assume that we have $3$ groups and on each group from $j=1,\dots,6$ we have $6$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2 =20.5$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2 =12.333$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2 =8.16667$

And we have this property

$SST=SS_{between}+SS_{within}$

The degrees of freedom for the numerator on this case is given by $df_{num}=df_{within}=k-1=3-1=2$ where k =3 represent the number of groups.

The degrees of freedom for the denominator on this case is given by $df_{den}=df_{between}=N-K=3*6-3=15$ .

And the total degrees of freedom would be $df=N-1=3*6 -1 =15$

The mean squares between groups are given by:

$MS_{between}= \frac{SS_{between}}{k-1}= \frac{12.333}{2}=6.166$

And the mean squares within are:

$MS_{within}= \frac{SS_{within}}{N-k}= \frac{8.1667}{15}=0.544$

And the F statistic is given by:

$F = \frac{MS_{betw}}{MS_{with}}= \frac{6.166}{0.544}= 11.326$

And the p value is given by:

$p_v= P(F_{2,15} >11.326) = 0.00105$

So then since the p value is lower then the significance level we have enough evidence to reject the null hypothesis and we conclude that we have at least on mean different between the 3 groups.

Part b

For this case the confidence interval for the difference woud be given by:

$(\bar X_B -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_B}{n_B} +\frac{s^2_C}{n_C}}$

The degrees of freedom are given by:

$df = n_B +n_C -2= 6+6-2=10$

The confidence level is 99% so then $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ and the critical value would be: $t_{\alpha/2}=3.169$

The confidence interval would be given by:

$(43.333 -41.5) - 3.169 \sqrt{\frac{0.6667}{6} +\frac{0.7}{6}}= 0.321$

$(43.333 -41.5) + 3.169 \sqrt{\frac{0.6667}{6} +\frac{0.7}{6}}=3.345$

7 0

3 years ago

How much acetic acid is in a 5 liter container that is marked 80% acetic acid. How much is water

Vinvika [58]

Answer:

1 liter of water

Step-by-step explanation:

If 80 % is acid that's means 4 liters of the 5 is acid. (0.8 * 5)

The remaining amount is 1

8 0

3 years ago

Read 2 more answers

I need help ASAP. I'm not good with math.

bonufazy [111]

Given:

The increase in pressure P is the linear function of the depth d.

$P(d)=0.445d+14.7$

The cost of dinner is $300 and $10 per students.

To find:

The initial value and rate of change and their interpretation.

Find the cost function C where n is the number of students.

Solution:

The slope intercept form of a linear function is

$f(x)=mx+b$ ...(i)

where, m is rate of change and b is y-intercept or initial value.

We have,

$P(d)=0.445d+14.7$ ...(ii)

From (i) and (ii), we get

$m=0.445,b=14.7$

The initial value is 14.7. It means, the pressure at sea level is 14.7 pounds psi.

Rate of change is 0.445. It means, the pressure is increasing by 0.445 pounds psi for every feet.

The cost of dinner is $300 and $10 per students.

Let C(n) be the total cost for dinner and n be the number of students.

Fixed cost = $300

Additional cost for 1 student = $10

Additional cost for n student = $10n

Now,

Total cost = Fixed cost + Additional cost

$C(n)=300+10n$

Therefore, the required cost function is $C(n)=300+10n$ .

8 0

2 years ago

What is 39700.0947 in scientific notation ?

Elden [556K]

Answer: 3.97000947 × 10^4

5 0

3 years ago

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A linear pair of<br> angles have<br> measures of 3m - 6<br> and 3m + 18. What<br> is the value of m?

timama [110]

Answer:

the value of m = 28°

Step-by-step explanation:

the sum of adjacent angles which form linear pair is 180°

so,

=》3m - 6° + 3m + 18° = 180°

=》6m + 12° = 180°

=》6m = 180° - 12°

=》m = 168° ÷ 6

=》m = 28°

4 0

3 years ago