Answer:
d. 3/8
Explanation:
Black coat color (B) is dominant over red coat color (b) and solid color (S) is dominant over spotted color (b).
BbSs was crossed with Bbss
BbSs x Bbss
Offspring:
<em>2 BBSs black, solid</em>
<em>2 BBss black, spotted</em>
<em>4 BbSs black solid</em>
<em>4 Bbss black, spotted</em>
<em>2 bbSs red, solid</em>
<em>2 bbss red spotted</em>
Total black solid = 6
Hence, the chance that black solid individual would be produced = 6/16 = 3/8.
The correct option is d.
<em>See the attached for the Punnet's square analysis.</em>
Scientific method would be the answer.
Answer: Saturated fatty acids
Explanation:
5 is a happens immediately after <span>meiosis.
</span>6 is b r<span>esults in genetically identical cells.</span>
This is based on my assumption that brown is dominant over blue.
Since both parent have parents who are homo_zygous recessive, this tells us that both parents will be hetero_zygous.
When you cross two hetero_zygous parents, it can produce these genotypic and phenotypic ratios:
<u>Genotypic</u>
BB : Bb : bb
1 : 2 : 1
<u>Phenotypic</u>
brown : blue
3 : 1
Therefore there is a 75% chance that they will produce a brown-eyed offspring.
