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Pavlova-9 [17]
3 years ago
6

55. In cocker spaniels, black coat color (B) is dominant over red (b), and solid color (S) is dominant over spotted (s). If Bb S

s were crossed with Bb ss, the chance that a black solid individual would be produced is a. 3/16. b. 1/3. c. 9/16. d. 3/8. e. 1/16.

Biology
1 answer:
jarptica [38.1K]3 years ago
3 0

Answer:

d. 3/8

Explanation:

Black coat color (B) is dominant over red coat color (b) and solid color (S) is dominant over spotted color (b).

BbSs was crossed with Bbss

BbSs   x   Bbss

Offspring:

<em>2 BBSs black, solid</em>

<em>2 BBss black, spotted</em>

<em>4 BbSs black solid</em>

<em>4 Bbss black, spotted</em>

<em>2 bbSs red, solid</em>

<em>2 bbss red spotted</em>

Total black solid = 6

Hence, the chance that black solid individual would be produced = 6/16 = 3/8.

The correct option is d.

<em>See the attached for the Punnet's square analysis.</em>

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