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Alexxandr [17]
3 years ago
10

Write the equation of a line perpendicular to y= 2x+ 2 that passes through the point (-1, -7).

Mathematics
1 answer:
Nataly [62]3 years ago
5 0

Answer:

all work is shown and pictured

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Mrs. Kim is teaching a 5th grade class. She is standing 48 feet in front of Lester. Carey is sitting to Lester's right. If Carey
victus00 [196]

Lester and Carey are 14 feet apart

Step-by-step explanation:

Mrs. Kim is teaching a 5th grade class

  • She is standing 48 feet in front of Lester
  • Carey is sitting to Lester's right
  • Carey and Mrs. Kim are 50 feet apart

We need to find how far apart Lester and Carey

Look to the attached figure

The positions of Mrs. Kim, Lester, and Carey formed a right triangle

∵ The distance between Mrs. Kim and Carey is 50 feet

∴ The length of the hypotenuse of the Δ = 50 feet

∵ The distance between Mrs. Kim and Lester is 48 feet

∴ The length of one leg of the Δ = 48 feet

The formula of length of the sides of the right Δ is:

(hypotenuse)^{2}=(leg_{1})^{2}+(leg_{2})^{2}

Substitute the length of the hypotenuse and the length of the given leg in the formula above

∵ (50)² = (48)² + (leg)²

∴ 2500 = 2304 + (leg)²

- Subtract 2304 from both sides

∴ 196 = (leg)²

- Take square for both sides

∴ 14 = leg

∵ This leg represents the distance between Lester and Carey

∴ The distance between Lester and Carey = 14 feet

Lester and Carey are 14 feet apart

Learn more:

You can learn more about the right triangle in brainly.com/question/1238144

#LearnwithBrainly

8 0
3 years ago
Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com
Rasek [7]

Answer:

a) The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

b)

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c) They are respected, as the upper bound of both intervals is below the new FAA recommendations.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve these questions.

Question a:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 100 - 1 = 99

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 99 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.9842

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9842\frac{20}{\sqrt{100}} = 4

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 183 - 4 = 179 pounds.

The upper end of the interval is the sample mean added to M. So it is 183 + 4 = 187 pounds.

The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

Question b:

Critical value is the same(same sample size and confidence level).

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9842\frac{23}{\sqrt{100}} = 4.6

The lower end of the interval is the sample mean subtracted by M. So it is 190 - 4.6 = 185.4 pounds.

The upper end of the interval is the sample mean added to M. So it is 190 + 4.6 = 194.6 pounds.

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c. The new FAA recommendations are 190 pounds for summer and 195 pounds for winter. Comment on these recommendations in light of the confidence interval estimates from Parts (a) and (b).

They are respected, as the upper bound of both intervals is below the new FAA recommendations.

7 0
2 years ago
At a dinner at Priya's favorite restaurant, the meal cost $18 and a sales tax of $1.71 was added to the bill.
Naily [24]

Answer:

$3.23

Step-by-step explanation:

1.71 ÷ 18 = 0.095 = 9.5%

9.5% × 34 = 3.23

5 0
2 years ago
H(t) = -10+ - 6<br>h()= -44​
lesya [120]

Answer:

-44

Step-by-step explanation:

4 0
3 years ago
Let g(x) = – x^2 + 4x + 3. Find and simplify g(-3).​
Evgen [1.6K]

Steps to solve:

g(x) = – x^2 + 4x + 3 when g(-3).

~Substitute x with -3.

g(-3) = -(-3)^2 + 4(-3) + 3

~Simplify

g(-3) = -9 - 12 + 3

~Simplify using PEMDAS

g(-3) = -18

Best of Luck!

7 0
3 years ago
Read 2 more answers
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