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lbvjy [14]
3 years ago
10

Suzie made a mistake in the following problem.

Mathematics
2 answers:
olga2289 [7]3 years ago
7 0
It's line2, she replaced 42 with 16 for some reason..
Flura [38]3 years ago
5 0

Answer: it is not line 2. The 16 comes from 4^2 which is 4.4=16. And the correct one is line 4, since it supposed to divide 42 by 5 and add the result to 16


Step-by-step explanation:


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3 0
3 years ago
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A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w
DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 21.5, \sigma = 4.7

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.175*4.7

X = 27.0225

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

Z = \frac{X - \mu}{\sigma}

1.04 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.04*4.7

X = 26.388

The lowest score that would meet the colleges requirement would be decreased to 26.388.

6 0
3 years ago
At a yearly basketball tournament, 64 different teams compete. After each round of the tournament, one-fourth of the teams remai
artcher [175]

Answer:

64*(1/4)^x

Step-by-step explanation:

64 is the starting number because it is given, and x represents how many rounds there are. 1/4 represents how much of the teams remain after each round.

5 0
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Simplify the product using the Distributive Property.
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The answer is  15h² + 26h - 21

<span>(5h – 3)(3h + 7) = 5h * 3h + 5h * 7 - 3 * 3h - 3 * 7 =
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Need help someone please help me
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Answer:

Its a i just took the test

Step-by-step explanation:

4 0
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