Given that the sides of the acute triangle are as follows:
21 cm
x cm
2x cm
Stated that 21 cm is one of the shorter sides of the triangle2x is greater than x, so it follows that 2x MUST be the longest side
For acute triangles, the longest side must be less than the sum of the 2 shorter sides
Therefore, 2x < x + 21cm
2x – x < 21cm
x < 21cm
If x < 21cm, then 2x < 42cm
Therefore, the longest possible length for the longest side is 42cm
Answer:
17155
Step-by-step explanation:
23500-27%-17155
To the nearest hundred: 17200.
Given:
A regular polygon with three vertices and side 14 cm.
To find:
Area of the regular polygon.
Solution:
We know that, a regular polygon has equal sides and equal interior angles.
The given regular polygon has three equal sides, it means it is an equilateral triangle.
The area of an equilateral triangle is:

Where, a is the side length of the triangle.
Putting
, we get




Therefore, the area of given regular polygon is 84.9 cm².
The answer is
B . Part to whole
Hope you have a nice day
Answer:
4
Step-by-step explanation:
solving equation 1
- log125 base 5√5=x
- [5√5=√(25×5)=√125]
- log125 base 125=x
- [From one of the principles of logarithm " logA base a =1]
- therefore, log125 base 125=1
- x=1
solving equation 2
- log 64 base 2√2=y
- [2√2=√(4×2)=√8]
- log 64 base√8=y
- 64=(√8)^y
- 64=8^(½y)
- 8²=8^(½y)
- (8 cancels in both equations and I evaluate the powers figures)
- 2=½y
- y=2×2=4
the product of x and y=x•y=1×4=4