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3 years ago

What is the name of the period that has the digits 913

Mathematics

1 answer:

Ugo [173]3 years ago

4 0

We can't tell what period the 913 is in until we see
the whole complete entire number.

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HELP ME FAST PLZ ❗️.

vfiekz [6]

Answer:

Step-by-step explanation:

You use law of sines, and get: AB/sin(53) = 7/sin(44)

You multiply both sides by sin(53), and get:

AB = 7*sin(53)/sin(44)

That means AB is 8.04776679886, which rounds to 8

7 0

3 years ago

5.22 write the decimal as a fraction or mixed number in simplest form

Vikentia [17]

Answer:

5 and 11/50

Step-by-step explanation:

5.22 = 261/50 = 5 and 11/50

5 0

3 years ago

Please help! Question posted above ^

emmainna [20.7K]

Answer:

( x^2 - 6 )^2

Step-by-step explanation:

x^4 -12x^2 +36

Find one factor
Factor by grouping

(x^2 - 6x) (x^2 - 6x)

*solution* ( x^2 - 6 )^2

8 0

3 years ago

Reduce 720/1080 little cunfused

Veronika [31]

To reduce a fraction, divide the numerator and the denominator equally until they reach the simplest whole number possible.

In this case, the numerator (720) and the denominator (1080) can both be divided by 360 to get 2/3, our reduced fraction.

8 0

3 years ago

Read 2 more answers

The speeds of vehicles traveling on a highway are normally distributed with an unkown population mean and standard deviation. A

Maksim231197 [3]

Answer:

The 90% confidence interval would be given by (60.09;69.91)

We are 90% confident that the true mean for the speeds of vehicles traveling on a highway is between 60.09 and 69.91 miles per hour.

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X =65$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=9 represent the sample standard deviation

n=11 represent the sample size

2) Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=11-1=10$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,10)".And we see that $t_{\alpha/2}=1.81$

Now we have everything in order to replace into formula (1):

$65-1.81\frac{9}{\sqrt{11}}=60.09$

$65+1.81\frac{9}{\sqrt{11}}=69.91$

So on this case the 90% confidence interval would be given by (60.09;69.91)

We are 90% confident that the true mean for the speeds of vehicles traveling on a highway is between 60.09 and 69.91 miles per hour.

3 0

3 years ago