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2 years ago

What is the name of the period that has the digits 913

Mathematics

1 answer:

Ugo [173]2 years ago

4 0

We can't tell what period the 913 is in until we see
the whole complete entire number.

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Andrew had 40 dollars to spend on paying the paint store was having a sale each color comes in one gallon container that cost $1

MAVERICK [17]

Answer:

yes, he would have enough money

He would need a total of 1.5 gallons to paint the wall .

the cost of 1.5 gallons is $18 dollars.

Andrew has 40. he has enough money

Step-by-step explanation:

total gallon needed to pain four walls = 3/8 x 4 = 1 1/2 gallons

total cost of 1 1/2 gallons = 1 1/2 x $12

to calculate this amount convert 1 1/2 to improper fraction

to convert to improper fraction, take the following steps :

1. Multiply the whole number by the denominator

2. Add the numerator to the answer gotten in the previous step

3. divide the number gotten in the previous step by the denominator

3/2 x $12 = $18

3 0

2 years ago

An electrician bought 120 feet of electrical wire and used 105 feet of it. What percent of the wire went unused? 15% 12. 5% 8. 7

Yuri [45]

Answer:

12.5%

Step-by-step explanation:

105 is what percent of 120?

you can use this proportion:

if/of = %/100

in this problem:

is = 105

of = 120

'what percent' = p/100

105/120 = p/100

cross-multiply to get:

120p = 10500

p = 10500/120

p = 87.5

So the electrician used 87.5%, out of 100%, meaning 12.5% went unused

5 0

2 years ago

Read 2 more answers

What integer represents the change in balance from Monday to Tuesday?

Bumek [7]

-34 is <span>integer represents the change in balance from Monday to Tuesday</span>

5 0

3 years ago

Given x^2 + y^2 = 36 and xy = -10 find x + y.

9966 [12]

This looks fun

ok so
we will use subsitution
xy=-10
divide both sides by x or y (I will choose y)
x=-10/y

sub -10/y fo x

(-10/y)^2+y^2=36
100/(y^2)+y^2=36
times both sides by y^2
100+y^4=36y^2
minus 36y^2 from both sides
y^4-36y^2+100=0
(y^2)^2-36(y^2)+100=0
quadratic formula
for
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$
x= $\frac{-(-36)+/- \sqrt{(-36)^2-4(1)(100)} }{2(1)}$
x= $18+/- 4\sqrt{14}$

sub
y=-10/x
y= $\frac{-10}{18+/- 4\sqrt{14}}$

so x+y= $18+/- 4\sqrt{14}$ + $\frac{-10}{18+/- 4\sqrt{14}}$
multiply first number by $\frac{18+/- 4\sqrt{14}}{18+/- 4\sqrt{14}}$ and add them

x+y= $\frac{(18+/- 4\sqrt{14})(18+/- 4\sqrt{14})-10}{18+/- 4\sqrt{14}}$
or
x+y= $\frac{81+22 \sqrt{14} }{5}$ or $\frac{81-22 \sqrt{14} }{5}$

8 0

2 years ago

Given a dilation with the origin O (0, 0), by observation determine the scale factor "K." DO, K = (5, 0) (10, 0) The dilation an

Eddi Din [679]

False because the scale factor is twice as much as it is in the equation so its false

6 0

3 years ago