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Bogdan [553]
3 years ago
11

I'M CRYING AND I'M DYING , HELP ME! SUPER EASY

Mathematics
1 answer:
Mrrafil [7]3 years ago
3 0
The answer for the spinner would be 1/2 because there are 4 R’s out of 8 so it would be 4/8 which simplifies to 1/2
The answer for the second one I’m sure would be .45 since rolling a one would add up to 9 and the total times it was rolled is 20 so if she rolls again she would have .45 since that’s the answer to 9/20



Hope this helps !


~Your Cookie Monster ( And don’t cry :) )
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What is 1,058/46. Please Explain in steps,and i will mark you brainlest
omeli [17]
You write it as 46 divide by 1058. 46 x 2 is the closest you will get to 100. 46 x 2 is 92. put it in and you have 138 left. multiply 46 x 3 and you will get 138. amswer is 23. remember to bring down the next number whwn dividing
4 0
3 years ago
In the figure below, O is between M and P, and N is the midpoint of MO. If =MP16 and =NO4, find OP.
Crazy boy [7]

Answer:

O is in between m and p so it is 6

Step-by-step explanation:

In the figure below, O is between M and P, and N is the midpoint of MO. If =MP16 and =NO4, find OP.

6 0
2 years ago
Please help, I rally need ir
Mnenie [13.5K]

Answer:

The one on the top at you’re right

3 0
3 years ago
In 1960, the population of a town was 14 thousand people. Over the course of the next 50 years, the town grew at a rate of 30 pe
andre [41]

SOLUTIONS

Given: Assume y is the population

\begin{gathered} t=0=1960,y=14030 \\ t=1=1961,y=14060 \\ so\text{ b = 14000} \\ so\text{ k = 30} \end{gathered}

The town grow at the rate of 30 people per year.

y=kt+14000y=30t+14000

(A) The population predicted to be in 2030 will be

\begin{gathered} 2030-1960=70 \\ y=30k+14000 \\ y=30(70)+14000 \\ y=2100+14000 \\ y=16100people \end{gathered}

(B) so when y = 15000, find t

\begin{gathered} y=15000 \\ y=30t+14000 \\ 15000=30t+14000 \\ 15000-14000=30t \\ 1000=30t \\ t=\frac{1000}{30} \\ t\approx33 \\ t=1960+33 \\ t=1993 \end{gathered}

3 0
1 year ago
Please help and thank you. ​
Marina CMI [18]

Answer:

4.

  • 400 ft elevation at 1 km and 3 km from the start
  • 300 ft/km average rate of change over the first 4 km

5.

  • length = 3.5 cm
  • width = 3.5 cm
  • height = 7.0 cm

6.

  • 6 mo: $1018.14
  • 5 yrs: $1196.89
  • avg incr: $3.28 per month

Step-by-step explanation:

<h3>4.</h3>

A graphing calculator is handy for solving problems involving cubic polynomials. You're interested in where the elevation is 400 ft. Since the value of f(x) is in hundreds of feet, you want to find x such that f(x) = 4.

Values of x where that is the case are x=1 and x=3, representing distances of 1 km and 3 km from the start of the road.

The average rate of change of elevation is the difference in elevation divided by the difference in distance from the start:

  average rate of change = (f(4) -f(0) hundred ft)/((4 - 0) km)

  = (19 -7)/4 hundred feet/km

  = 12/4  hundred feet/km = 300 ft/km

___

<h3>5.</h3>

You want to find x when ...

  A(x) = 122.5 cm²

  10x² = 122.5 cm² . . . . substitute the given expression for A(x)

  x² = 12.25 cm² . . . . . . divide by 10

  x = √(12.25 cm²) = 3.5 cm . . . . take the square root

The diagram tells you ...

  length = width = x = 3.5 cm

  height = 2x = 7.0 cm

___

<h3>6.</h3>

Evaluate the given expression for the different values of m:

  $1000·1.003^6 ≈ $1018.14 . . . . 6-month value

  $1000·1.003^60 ≈ $1196.89 . . . . 5-year value

The increase is $1196.89 -1000.00 = $196.89. That increase took place over 60 months, so the average increase per month is ...

  $196.89/(60 mo) ≈ $3.28 per mo . . . . average per month over 5 years

8 0
3 years ago
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