A force of 182.6 lb should be applied to lift 700 lb object.
<h3>How to calculate the force?</h3>
Let the force required to lift be F
Total length = 29 in.
Distance of short end from pivot = in.
Distance from long end = 29-6 = 23 in.
Now Equating moments
F × 23 = 700x6
23F = 4200
F = 4200/23
= 182.6 lb
A force of 182.6 lb should be applied to lift 700 lb object.
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The answer is 17/19 because if you divide 85 by five equals 17 and 95 divided by 5 equals is 19 and since 5 is the highest factor of 85 and 95 the answer is correct.
1/2*bh=75
1/2*bb=75
b^2=150
b=rt(150)=12.2
not sure what you mean by link, but 12.2 is approximately the length you're seeking
I think it’s Step 2 your welcome
Answer:
So we can use geometric progression each time multiplying by 0.0475
so thats (275*0.0475)*10
So that means that we would get
130.625 so we subtract that from 275
275-130.625=144.375
That would be
Step-by-step explanation:
