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NISA [10]
3 years ago
8

Need help please quick

Mathematics
2 answers:
Charra [1.4K]3 years ago
5 0
Every 2 games they lost 10
Triss [41]3 years ago
4 0

Answer: For every 2 games won there 10 games lost

Step-by-step explanation:

Hope I helped

-Hunter Cross

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Please answer this correctly
lana66690 [7]

Answer:

  698 cm²

Step-by-step explanation:

The volume is given by ...

  V = LWH

Filling in the given values, we have ...

  1020 = (17)(5)y . . . . . . . using L=17, W=5, H=y

  y = 1020/(17·5) = 12

The surface area is given by ...

  A = 2(LW +H(L+W))

  A = 2(17·5 +12(17+5)) = 2(85 +264) . . . . . . . using L=17, W=5, H=y=12

  A = 698 . . . . square centimeters

6 0
3 years ago
the singh and robinson families planned a trip to busch gardens. they needed to buy one ticket per person and then pay for parki
hjlf

Let x represent cost of each ticket and y represent cost of parking.

We have been given that the Singh's spent $335 for 5 people and parking. We can represent this information in an equation as:

5x+y=335...(1)

We are also told that the Robinson spent $465 for 7 people and parking. We can represent this information in an equation as:

7x+y=465...(2)

Now we will use elimination method to solve our given system of equations.

Upon subtracting equation (1) from equation (2), we will get:

7x-5x+y-y=465-335

2x=130

\frac{2x}{2}=\frac{130}{2}

x=65

Therefore, the each ticket costs $65.

Upon substituting x=65 in equation (1), we will get:

5(65)+y=335

325+y=335

325-325+y=335-325

y=10

Therefore, the parking costs $10.

5 0
3 years ago
The common factors of 4p3mn2 and 2pm2n3 is​
pantera1 [17]

Given:

The given terms are

4p^3mn^2 and 2pm^2n^3

To find:

The common factors of given terms.

Solution:

We have,

4p^3mn^2 and 2pm^2n^3

The factor forms are

4p^3mn^2=2\times 2\times p\times p\times p\times m\times n\times n

2pm^2n^3=2\times p\times m\times m\times n\times n\times n

The common factors are 2, p, m, n, n. So,

Common factors = 2\times p\times m\times n\times n

                            = 2pmn^2

Therefore, the common factor of given terms is 2pmn^2.

7 0
3 years ago
Use mental math to solve 4576 + 2842
allsm [11]
The answer is 7418.

Hope this helps
6 0
3 years ago
Read 2 more answers
A chemist examines 15 geological samples for potassium chloride concentration. The mean potassium chloride concentration for the
Lelu [443]

Answer:

95% Confidence interval: (0.375,0.377)

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = 0.376 cc/cubic meter

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 0.0012

Degree of freedom =

=n-1\\=15-1\\=14

95% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.05} = \pm 2.145  

0.376 \pm 2.145(\dfrac{0.0012}{\sqrt{15}} )\\\\ = 0.376 \pm 0.0006\\\\ = (0.3754,0.3766)\approx (0.375,0.377)  

(0.375,0.377) is the required 95% confidence interval for the population mean potassium chloride concentration.

5 0
3 years ago
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