Answer:
a.
<u>Increasing:</u>
x < 0
x > 2
<u>Decreasing:</u>
0 < x < 2
b.
-1 < x < 2
x > 2
c.
x < -1
Step-by-step explanation:
a.
Function is increasing when it is going up as we go rightward
Function is decreasing when it is going down as we go rightward
We can see that as we move up (from negative infinity) until x = 0, the function is increasing. Also, as we go right from x = 2 towards positive infinity, the function is going up (increasing).
So,
<u>Increasing:</u>
x < 0
x > 2
The function is going down, or decreasing, at the in-between points of increasing, that is from 0 to 2, so that would be:
<u>Decreasing:</u>
0 < x < 2
b.
When we want where the function is greater than 0, we basically want the intervals at which the function is ABOVE the x-axis [ f(x) > 0 ].
Looking at the graph, it is
from -1 to 2 (x axis)
and 2 to positive infinity
We can write:
-1 < x < 2
x > 2
c.
Now we want when the function is less than 0, that is basically saying when the function is BELOW the x-axis.
This will be the other intervals than the ones we mentioned above in part (b).
Looking at the graph, we see that the graph is below the x-axis when it is less than -1, so we can write:
x < -1
Answer:
Uwm am I famous but I'm doin dis for free points sowwy
Answer:
Step-by-step explanation:
I uploaded a picture hope it helps
Answer:
Step-by-step explanation:
∠1 + ∠2 = 180 Linear pair
∠4 + ∠5 +∠ 3 = 180 form straight line
∠1 + ∠2 = ∠4 + ∠5 + ∠3 from statement 1 and 2
∠3 +∠2 = ∠4 + ∠5 + ∠3 ∠1 and ∠3 are vertically opposite angles.
∠2 = ∠4 + ∠5 Proved
Answer:
30 km/h car
Step-by-step explanation:
From analysis the car traveling at 30 km/h has greater kinetic energy
we can deduce it from the expression of kinetic energy which is

Assuming the mass m= 1 kg
For the 30 km/h

For the 15 km/h

Though the kinetic energy is a function of mass and velocity, but from our analysis the faster moving object has more KE