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3 years ago

Look at the given angle.

Mathematics

2 answers:

mylen [45]3 years ago

6 0

Other ways are m<1, YFP and m<F.

The angle is an acute angle because it is less than a right angle (less than 90 degrees).

ki77a [65]3 years ago

5 0

A)
1) YPF
2) F
3) 1

b) Acute, because the angle clearly is less thant 90°.

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Which set of coefficients of the terms in the Expansion of the binomial (x+y)^3 is correct?

lora16 [44]

A is correct.

Why? After opening the brackets we can see the equation as $x^{3} + 3x^{2}y + 3y^{2}x + y^{3}$

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3 years ago

Holly Cuts 3 pans of brownies into eighths. How many 1/8 size brownie pieces does she have?

Anuta_ua [19.1K]

She has 24 pieces, 8x3=24.
Plz rate 5 stars

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3 years ago

Read 2 more answers

Researchers at Gallup were interested in whether there was a decrease in the proportion of nonretirees (in other words, people w

Lera25 [3.4K]

Answer:

A. We have extremely strong evidence to reject H0.

Step-by-step explanation:

Let P be the proportion of non-retirees in 2015 who did not think that Social Security would be able to pay a retirement benefit by the time that they retire.

According to the data null and alternative hypotheses should be:

$H_{0}$ : P=0.60

$H_{a}$ : P<0.60

Test statistics is -4.29 and p-value of the statistics is p<0.001

At every significance levels higher than 0.001, we can reject the null hypothesis since p<0.001.

8 0

4 years ago

A DVD has a diameter of 26 centimeters. What is the area of the DVD? Round your answer to the nearest hundredth. Use 3.14 for π.

Alinara [238K]

Answer:

A =530.66 cm^2

Step-by-step explanation:

A DVD is a circle so we can use the formula for area of a circle

A = pi r^2

We can find the radius from

r = d/2 where d is the diameter

r = 26/2

r = 13

A = pi *13^2

A = pi *169

Substituting in for pi

A = (3.14) * 169

A =530.66

7 0

3 years ago

Using the Law of Cosines, in triangle DEF, if e=18yd, d=10yd, f=22yd, find measurement of angle D

Ivahew [28]

Check the picture below.

$\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}
\\\\\\
\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}=cos(C)\implies cos^{-1}\left(\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}\right)=\measuredangle C\\\\
-------------------------------\\\\
\begin{cases}
d=10\\
e=18\\
f=22
\end{cases}\implies cos^{-1}\left(\cfrac{{{ 18}}^2+{{ 22}}^2-10^2}{2(18)(22)}\right)=\measuredangle D$

$\bf \implies cos^{-1}\left(0.893\overline{93}\right)=\measuredangle D\implies 26.63^o\approx \measuredangle D$

7 0

3 years ago