Step-by-step explanation:
since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

So probabaility for
is

So expected frequency for
is
(or
.
Answer:
It would be $465 marked up.
Step-by-step explanation:
55% of 300 is 165.
So marked up its 465 and marked down its 135.
3610.201 this the answer if u want in de imal
Answer:
Go to math
Step-by-step explanation:
Answer:
4743246
Step-by-step explanation: