Answer:
we have two solution x = 5 and x = 11
but in given problem x = 5 and x = –11
thus, only one of his solution x = 5 is correct
Step-by-step explanation:
Given
–2|8 – x| – 6 = –12
adding 6 both sides
–2|8 – x| – 6 +6= –12 +6
–2|8 – x| = –6
dividing both side by -2
–2|8 – x| /-2 = –6/-2
=>|8 – x| = 3
we know that
in modulus function |Y| = -y or y
Thus
|8 – x| = 3
can be written as
8-x = 3 or 8- x = -3
8-x-3 = 0 or 8-x+3 = 0
5-x = 0 or 11 -x = 0
x = 5 or x = 11
thus, we have two solution x = 5 and x = 11
but in given problem x = 5 and x = –11
thus, only one of his solution x = 5 is correct
