Answer:
For bbff we have only 6.3% probability
Step-by-step explanation:
If the parents are heterozygous for both traits, them they are represented by:
BbFf × BbFf
Parent 1: BbFf
Parent 2: BbFf
We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.
By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:
Genotype Count Percent
bBfF 4 25
BBfF 2 12.5
bBFF 2 12.5
bBff 2 12.5
bbfF 2 12.5
BBFF 1 6.3
BBff 1 6.3
bbFF 1 6.3
bbff 1 6.3
For bbff we have only 6.3% probability
For any point to be in the first quadrant, it must have a positive "x" value and "y" value.
If x = 1 then y = 2, a point with both x and y positive values which would be in the First Quadrant.
Answer:
Area of the figure = 254.5 cm²
Step-by-step explanation:
<u><em>Area of rectangle = Length × Width</em></u>
<u><em>Area of triangle = 1/2(base × Height)</em></u>
<em>Dividing the figure into parts for convenience</em>
So,
Rectangle 1 (the uppermost):
4 × 6 = 24 cm²
Rectangle 2 (below rectangle 1):
15 × 8 = 120 cm²
Rectangle 3 (with rectangle 2):
11 × 4 = 44 cm²
Triangle 1 :
1/2(7 × 19) = 133/2 = 66.5 cm²
<em>Now adding up all to get the area of the figure:</em>
Area of the figure = 24 + 120 + 44 + 66.5
Area of the figure = 254.5 cm²
Answer: 1.6, but if your looking for rounding numbers, its 2. I suggest 1.6 though.
Step-by-step explanation: hope this helps :)