All categories

3 years ago

Can someone please help me! This is trigonometry

Mathematics

2 answers:

emmasim [6.3K]3 years ago

7 0

Use cosine rule to find both.

Finding theta.
4² = 5² + 2² - 2(5)(2)cosθ
16 = 25 + 4 - 20cosθ
-13 = -20cosθ
13/20 = cosθ

θ ≈ 49°

Finding x.
Use cosine rule again for the bigger triangle.
x² = 5² + 3² - 2(5)(3)cos(49)
x² = 25 + 9 - 30cos(49)
x² = 24.9822237...
x ≈ 4 cm

It is advised that you plug in these numbers yourself, because of rounding errors. These answers are based off of the initial rounding of θ

lbvjy [14]3 years ago

3 0

Tan=opposite over adjacent so the equation is tan=4/1 x=4

You might be interested in

Right triangle XYZ is shown below with the dimensions given in yards (yd).

zavuch27 [327]

we know that

cos x=XZ/XY

XZ=28 yd

XY=83 yd

cos x=28/83

X=arc cos (28/83)---------> X=70.28°---------> X=70.3°

the answer is

X=70.3°

8 0

4 years ago

Find the GCF of each pair of numbers.

e-lub [12.9K]

10 77 uhhh 45 dont know

5 0

3 years ago

Prove that 1³+2³+....n³=n²(n+1)²/4. principle of mathematics induction

alex41 [277]

<h3>The Simplified Question:-</h3>

$\sf 1^3+2^3\dots n^3=\dfrac{n^2(n+1)^2}{2}$

$\\ \sf\longmapsto 1^3+2^3+\dots n^3=\left(\dfrac{n(n+1)}{2}\right)^2$

<h3>Solution:-</h3>

Let

$\\ \sf\longmapsto P(n)=1^3+2^3\dots n^3=\left(\dfrac{n(n+1)}{2}\right)^2$

For n=1

$\\ \sf\longmapsto P(1)=\left(\dfrac{1(1+1)}{2}\right)^2$

$\\ \sf\longmapsto P(1)=\left(\dfrac{1(2)}{2}\right)^2$

$\\ \sf\longmapsto P(1)=\left(\dfrac{2}{2}\right)^2$

$\\ \sf\longmapsto P(1)=(1)^2$

$\\ \bf\longmapsto P(1)=1=1^3$

Let k be any positive integer.

$\\ \sf\longmapsto P(k)= 1^3+2^3\dots k^3=\left(\dfrac{k(k+1)}{2}\right)^2$

We have to prove that p(k+1) is true.

consider

$\sf 1^3+2^3\dots k^3+(k+1)^3$

$\\ \sf\longmapsto \left(\dfrac{k(k+1)}{2}\right)^2+(k+1)^3$

$\\ \sf\longmapsto \dfrac{k^2(k+1)^2}{4}+(k+1)^3$

$\\ \sf\longmapsto \dfrac{k^2(k+1)^2+4(k+1)^3}{4}$

$\\ \sf\longmapsto \dfrac{k+1)^2\left\{k^2+4k+4\right\}}{4}$

$\\ \sf\longmapsto \dfrac{(k+1)^2(k+2)^2}{4}$

$\\ \sf\longmapsto \dfrac{(k+1)^2(k+1+1)^2}{4}$

$\\ \sf\longmapsto \left(\dfrac{(k+1)(k+1+1)}{2}\right)^2$

$\\ \sf\longmapsto (1^3+2^3+3^3\dots k^3)+(k+1)^3$

Thus P(k+1) is true whenever P(k) is true.

Hence by the Principal of mathematical induction statement P(n) is true for $\bf n\epsilon N.$

Note:-

We can solve without simplifying the Question .I did it for clear steps and understanding .

<h3>Learn More:-</h3>

brainly.com/question/13253046?

brainly.com/question/13347635?

6 0

3 years ago

Read 2 more answers

I need to solve: -3(8x); x = 1/4. Using substitution ro find the value of expression

marishachu [46]

First, find the value of the expression within the parentheses, which is 8x. Since x=1/4, 8x=8/4 or 2. Next, multiply this value by -3. -3*2=-6

5 0

3 years ago

Will give brainlist<br><br> explain how the number 0.10 likelihood is unlikely

Mrac [35]

Answer

Step-by-step explanation 0 indicates and unlikely event large numbers indicate greater likli hood proply around 1/2 indicates that niether is unlikely can i have brailies now

3 0

3 years ago