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3 years ago

When is a relation a function

Mathematics

1 answer:

Vaselesa [24]3 years ago

8 0

Answer:

A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y. That is, given an element x in X, there is only one element in Y that x is related to. For example, consider the following sets X and Y.

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Helppp me the awnser is in the picture

Sindrei [870]

Y = 5x + 3 please mark me brainliest and comment if you want an explanation.

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3 years ago

In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!

g100num [7]

the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

Step-by-step explanation:

$x^{3}$ = $- 64$

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We can write 64 as $4^{3}$

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using the identity ( $x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} )$ )

we get,

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= $(x+4)(x^{2} -4x+16)$ ....................(1)

solving the quadratic equation ,

$x^{2} -4x+16$ =0

solutions of this quadratic equation can be obtained by

$x=-b +- \sqrt{b^{2}-4ac } /2a$

let use y for factors

$x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16} / 2*x^{2}$

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$x=4+-\sqrt{16-64}/2$

$x=4+-4\sqrt{3i} /2$

<u /> $x=2+-2\sqrt{3i}$ ..................(2)

from the equation 1 we have,

$x-4=0$

which gives solution $x=4$

and from equation 2 we got $x=2+-2\sqrt{3i}$

so the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

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2 years ago

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SOVA2 [1]

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First add c to both sides
g+c= y+x
Subtract y from both sides
g+c-y= x
That should be your final answer (we cannot come up with an actual digit for x because there are no numbers in this equation we simply can make an equation for x)

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3 years ago

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What is 6 6/7 - 2 3/8

lilavasa [31]

Answer: exact form: 251/56, decimal form 4.482, mixed number form 4 27/56

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"The graph of F(x), shown below, resembles the graph of G(x) = x2, but it has been changed somewhat. Which of the following coul

SpyIntel [72]

G(x)=x²
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Answer:
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3 years ago

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When is a relation a function​

When is a relation a function