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s2008m [1.1K]
2 years ago
15

8 equal sized boxes of trinkets are delivered to Jess home and all the trinkets are unloaded into one pile. Jess adds 14 of her

own trinkto the pile. The trinket are then equally divided into 6 piles. Jess determines that each pile contains 9 trinkets. (Write an equation and solve the equation to find the number of trinkets that were originally in each of the 8 delivery boxes)
Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
6 0

Answer:

now lemme answer this. u did the same to me.. came to my question and answered wrong i mean nothing.

revenge

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cupoosta [38]

Answer:

2^3·2^2 = 2^3+2 = 2^5  

Step-by-step explanation:

Diego was trying to write 2^3 · 2^2

He wrote  2^3·2^2 = 2^3*2 = 2^6  

But this is wrong because when bases are same exponents are added.

This is the law of exponents.

The correct form would be

2^3·2^2 = 2^3+2 = 2^5  

For understanding it better we can write it like this

2^3·2^2 =

There are 3 two and 2 twos .When totaled there are 5 two not 6 twos.

5 0
2 years ago
Amy’s age plus Betty’s age is 29 years. Amy’s plus Carl’s age is 27 years. Betty’s plus Carl’s age is 22 years. What is the diff
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Answer: 12

Step-by-step explanation

4 0
3 years ago
PLSS HELP!! VERY EASY.
gogolik [260]

Answer:

35 ways

Step-by-step explanation:

Alex has 9 friends and wants to invite 5 friends. Since Alex requires two of his friends who are twins to come together to his birthday party, since the two of them form a group, the number of ways we can select the two of them to form a group of two is ²C₂ = 1 way.

Since we have removed two out of the nine friends, we are left with 7 friends. Also, two friends are already selected, so we are left with space for 3 friends. So, the number of ways we can select a group of 3 friends out of 7 is ⁷C₃ = 7 × 6 × 5/3! = 35 ways.

So, the total number ways we can select 5 friend out of 9 to  party come to the birthday include two friends is  ²C₂ × ⁷C₃ = 1 × 35 = 35 ways

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3 years ago
A
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Answer:

3,25-2,5=0,75 it is equal to 3/4 so D

7 0
2 years ago
Solve for c: 2(4c-7) is greater than or equal to 8(c-3)
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2(4c-7)\geq8(c-3)\ \ \ \ |\text{use distributive property}\\\\(2)(4c)-(2)(7)\geq(8)(c)-(8)(3)\\\\8c-14\geq8c-24\ \ \ \ |-8c\\\\-14\geq-24\ \ \ TRUE\\\\\text{therefore your answer is}\ x\in\mathbb{R}\ (all\ real\ numbers)

3 0
3 years ago
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