What are the numbers that have an absolute value of 4?

Mathematics

2 answers:

jolli1 [7]3 years ago

3 0

B, G

Absolute value = neglect the sign

Norma-Jean [14]3 years ago

3 0

B and g... absolute value is just the number itself

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3x+2-5x=10 what is X

Advocard [28]

Answer:

x = -4

Step-by-step explanation:

Solve for x:

3 x - 5 x + 2 = 10

Grouping like terms, 3 x - 5 x + 2 = 2 + (3 x - 5 x):

2 + (3 x - 5 x) = 10

3 x - 5 x = -2 x:

-2 x + 2 = 10

Subtract 2 from both sides:

(2 - 2) - 2 x = 10 - 2

2 - 2 = 0:

-2 x = 10 - 2

10 - 2 = 8:

-2 x = 8

Divide both sides of -2 x = 8 by -2:

(-2 x)/(-2) = 8/(-2)

(-2)/(-2) = 1:

x = 8/(-2)

The gcd of 8 and -2 is 2, so 8/(-2) = (2×4)/(2 (-1)) = 2/2×4/(-1) = 4/(-1):

x = 4/(-1)

Multiply numerator and denominator of 4/(-1) by -1:

Answer: x = -4

7 0

3 years ago

Find the length of the following two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16

andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

$r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)} dt$

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

$r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)} dt$