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ki77a [65]
3 years ago
5

While resaerching facts on the planet earth kate learned that a true earth day

Mathematics
1 answer:
romanna [79]3 years ago
4 0

Answer:

mmmmmmm hmmmmmm

Step-by-step explanation:

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Which type of graph would allow us to Quickly see how many months between 100 and 200 student were treated
lisov135 [29]

Answer:

Histogram

Step-by-step explanation:

7 0
4 years ago
How are you today? i still have some homework to do.
MakcuM [25]

Answer:

Same lol

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
What is the value of y?<br> y<br> 60°<br> 80°
user100 [1]

Step-by-step explanation:

60° + 80° + y = 180° ( being straight angle )

140° + y = 180°

y = 180° - 140°

y = 40°

5 0
2 years ago
WILL GIVE BRAINLIST Examine the diagram and information to answer the question. A circle in the coordinate plane has a radius of
DanielleElmas [232]

Answer:  To find the equation of the circle, it is not necessary to find the legs of the triangle first.  

The length of the legs (equal) is 3√2 or  4.243

Step-by-step explanation:

The equation for a circle is similar to the Pythagorean Theorem

       a²   +   b²     = c²

( x - h )² + ( y - k )² = r², where ( h, k ) is the center and r is the radius.

The a and b terms are  changed to allow insertion of  h and k to locate the center of the circle on a Cartesian plane.

You can get the information needed from

Given: radius =6 and  "a center at the point (3,2)"

Substitute  3 for h and  2 for k  and  6 for r

( x - 3 )² + ( y - 2 )² = 6²    This is the equation of the circle .

From the diagram, it appears that x-3 = y-2

So, in the equation, we can substitute 2(x²) = 36

x² = 36/2 .   x² = 18

√x² = √18 = √9(2)

x = 3√2   =4.2426

the length of the horizontal leg is 4.243

Substitute for x in to find  x+3  the coordinate (x,2)

the coordinate x, 2 is  (7.24, 2)

Substitute for y in to find  y+2, the length of the vertical leg is 4.243.

y + 2 = 6.243  

So the coordinate (x,y) on the circle is (7.24, 6.24)

This does not account for Step 1 and  Step 2 in the question, matching expressions or equations to the steps. I hope you will be able to sort that our with the information here.

7 0
3 years ago
Cancel the common factor of the numerator and the denominator and write specified expression
lisabon 2012 [21]

Step-by-step explanation:

<em>Hello</em><em>,</em>

<em>I</em><em> </em><em>hope</em><em> </em><em>you</em><em> </em><em>mean</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>that</em><em> </em><em>exists</em><em> </em><em>in</em><em> </em><em>numerator</em><em> </em><em>and</em><em> </em><em>denominator</em><em>,</em><em>right</em><em>.</em>

<em>so</em><em>,</em><em> </em><em>Let's</em><em> </em><em>look</em><em> </em><em>for</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em>, </em>

<em>here</em><em>,</em><em> </em><em>the</em><em> </em><em>expression</em><em> </em><em>is</em><em>, </em>

<em>=</em><em>4</em><em>(</em><em>x-2</em><em>)</em><em>/</em><em> </em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em><em>(</em><em>x-2</em><em>)</em>

<em>so</em><em>,</em><em> </em><em>here</em><em> </em><em>we</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>is</em><em> </em><em>(</em><em>x-2</em><em>)</em>

<em>now</em><em>,</em><em> </em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>it</em><em>.</em><em> </em><em>And</em><em> </em><em>after</em><em> </em><em>cancelling</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em>=</em><em>4</em><em>/</em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em>

<em>Note</em><em>:</em><em>{</em><em> </em><em>we</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>if</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factors</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>multiply</em><em> </em><em>form</em><em>.</em><em>}</em>

<em><u>Hope it helps</u></em><em><u> </u></em>

3 0
3 years ago
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