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3 years ago

What’s the answer ??? (SOMEONE PLEASE HELP)

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

5 0

It's the first one. That is a perfect square polynomial, which, when factored, will give you the same binomial twice, or multiplicity 2. It will factor to $g(x)=(x+9) ^{2}$ , where the vertex (h, k), is (-9, 0).

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Five more than the sum of a number and ten

Montano1993 [528]

X=5y+10 this is the answer

4 0

3 years ago

Helpp plz i'll mark brainliest (see picture). <br> The second part is, What is the value of y?

Art [367]

Answer:

116*

Step-by-step explanation:

36* + 28* = 64*

180* - 64* = 116*

4 0

3 years ago

CAN SOMEONE HELP ME PLEASE???

lana66690 [7]

Answer:

Step-by-step explanation: First, you need to write all your data down from least to greatest. Next, count up all the numbers to see how many students. Then you want to find the mean which is average (add then divide). Median is the middle so you will x each number out till you get to the middle, and if the middle is 2 numbers, you find the average of them to find the median. Mode means most often. Range is highest minus lowest. And you can do the next 2.

4 0

3 years ago

Read 2 more answers

The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m

UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of $\bar X$ Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

4 0

3 years ago

The average value of the function y = x² – 1 on [0, 12] is

shusha [124]

Answer:

47.

Step-by-step explanation:

1) the rule:

$f_{avr}=\frac{1}{b-a} \int\limits^b_a {f(x)} \, dx ,$

where a;b are 0 and 12, f(x)=x²-1.

2) according to the rule above:

$f_{avr}=\frac{1}{12-0} \int\limits^{12}_0 {(x^2-1)} \, dx=\frac{1}{12}(\frac{x^3}{3}-x)|^{12}_0=48-1=47.$

3 0

2 years ago