3 years ago

What is the answer to this 100/10

Mathematics

1 answer:

vladimir1956 [14]3 years ago

6 0

Answer:

Step-by-step explanation:

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Based on past experience, a telemarketing firm has found that calls to prospective customers take an average of 2.0 minutes, wit

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Answer: Our required probability would be 0.9641.

Step-by-step explanation:

Since we have given that

Number of hours he works a day = 8

So, Number of minutes he worked in a day = $8\times 60=480\ minutes$

Number of calls = 220

So, Average $=\bar{x}=\dfrac{480}{220}=2.18\ minutes$

Standard deviation $=s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.5}{\sqrt{220}}=0.10$

Mean = μ = 2.0 minutes

Standard deviation = σ = 1.5 minutes

Using the normal distribution, we get that

$z=\dfrac{\bar{x}-\mu}{s}\\\\z=\dfrac{2.18-2.0}{0.10}\\\\z=1.8$

So, the probability that Albert will meet or exceed his quota would be

$P(X\leq 2.18)=P(z\leq 1.8)=0.9641$

Hence, our required probability would be 0.9641.

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3 years ago

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