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2 years ago

How many times greater is the value of the 5 in 500 than the value of the 5 in 50

Mathematics

1 answer:

densk [106]2 years ago

4 0

It is 10 times bigger. It is easy because you can do 50 x 10 which is 500 and you know it is 10 times bigger.

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umka21 [38]

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Given sets X, Y, Z, and U, find the set Xn(X - Y) using the listing method.

Aliun [14]

Answer:

{f, a}

Step-by-step explanation:

Given the sets:

X = {d, c, f, a}

Y = {d, e, c}

Z ={e, c, b, f, g}

U = {a, b, c, d, e, f, g}

To obtain the set X n (X - Y)

We first obtain :

(X - Y) :

The elements in X that are not in Y

(X - Y) = {f, a}

X n (X - Y) :

X = {d, c, f, a} intersection

(X - Y) = {f, a}

X n (X - Y) = elements in X and (X - Y)

X n (X - Y) = {f, a}

6 0

2 years ago

Determine the function which corresponds to the given graph. (3 points)

damaskus [11]

Answer:

The center of the circle is c=50 and radius of the circle is $r=\sqrt{3}$

Step-by-step explanation:

Given circle equation is

$x^2-4x+y^2+14y=-50\hfill(1)$

Equation (1) can be written as $x^2-4x+y^2+14y+50=0\hfill(2)$

we know that the equation of the circle is of the form

$x^2+y^2+2gx+2fy+c=0\hfill(3)$

with centre (-g,-f) and radius= $\sqrt{g^2+f^2-c}$

when, g,f and c are constants

Now comparing the (2) and (3) equations we get 2g=-4

$g=\frac{-4}{2}$

$g=-2$

$2fy=14$

$f=\frac{14}{2}$

$f=7$

and $c=50$

Now to find the centre and radius of the given circle equation, substituting the values of g,f,c in the formulae of centre and radius

centre=(-g,-f)

=(-(-2),-7)

centre=(2,7)

Radius= $\sqrt{g^2+f^2-c}$

= $\sqrt{(-2)^2+(7)^2-50}$

= $\sqrt{4+49-50}$

= $53-50$

Radius= $\srqt{3}$

The center of the circle is c=50 and the radius of the circle equation $r=\sqrt{3}$

6 0

2 years ago