The first step to solving this expression is to factor out the perfect cube
![\sqrt[3]{m^{2} n^{3} X n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bm%5E%7B2%7D%20%20n%5E%7B3%7D%20X%20n%5E%7B2%7D%20%20%20%7D%20)
The root of a product is equal to the product of the roots of each factor. This will make the expression look like the following:
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%20%7D%20)
Finally,, reduce the index of the radical and exponent with 3
n
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%20%7D%20)
This means that the correct answer to your question is n
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%7D%20)
.
Let me know if you have any further questions
:)
The first one in incorrect , it should be 130 but the rest are correct !
Answer:
11.)60 degrees the lines on the triangle (the lil dashes) mean that that all the sides are equal making all the angles equal as well so all the angles equal 60 degrees.
12.) no, because in order for all the sides to be 12ft the angles have to be 60 degrees and this one is only 58 degrees so it wont exactly reach 12ft
Step-by-step explanation:
hope this helps :P
Observe the given data distribution table carefully.
The 5th class interval is given as,

The upper limit (UL) and lower limit (LL) of this interval are,

Thus, the upper-class limit of this 5th class is 17.4.
Answer:
area of triangle= 1/2*h*b
= 1/2*6*16
=3*16
= 48 yd²
This is your answer. If I'm right so,
Please mark me as brainliest. thanks!!!