Answer:
A, B, F
Step-by-step explanation:
took the test
Find the GCF of 80 and 32.
I'd start by identifying possible integer factors of both 80 and 32:
80: {1,2,4,5,8,10,16,20, 40, 80}
32: {1, 2,4, 8, 16, 32}
Working backwards, we see that the first factor that is represented in both lists is 16. Is 80 evenly divisible by 16? Yes; the quotient is 5.
Is 32 evenly divisible by 16? Yes; the quotient is 2.
You could writet 80 + 32 as 16(5 + 2). This is a product equal to 112, just as 80 + 32 = 112.
I belive the answer is 1.
This is because out of 22 ribbon there are 10 which are bue so the probability of blue ribbons is 10/22 and probability of red ribbon is 12/22. So your question was the probability of choosing a red ribbon then a blu ribbon. Because of the word "then" , this means it is simply asking you to add their probablity so after adding 10/22 with 12/22 your answer will come to 22/22 which is equal to 1.