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Tresset [83]
3 years ago
13

5l of 70% alcohol solution was mixed with 9l of pure water what is the concentration of the mixture

Mathematics
1 answer:
ElenaW [278]3 years ago
6 0

The new mixture has a total volume of 5 L + 9 L = 14 L.

70% of the 5 L alcohol solution is alcohol, so that it contributed 3.5 L of alcohol to the mixture. The pure water contributed no alcohol. So in the mixture, the concentration of alcohol is

3.5 L / 14 L = 0.25, or 25%

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olasank [31]
Given the fraction 5/12 and 9/16, the least common denominator can be get by giving the possible common multiples of 12 and 16.

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3 0
3 years ago
Please help urgent!!
USPshnik [31]

Answer:

Q M \cong R M \Rightarrow definition of midpoint

\overline{P M} \cong \overline{P M} \Rightarrow Reflexive property of congruence

\Delta P Q M \cong \Delta P R M \Rightarrow SSS congruence postulate

\angle Q \cong \angle R \Rightarrow CPCTC theorem

Step-by-step explanation:

Step 1: Since, M is the midpoint of the line segment QR.  

\overline{Q M} \cong \overline{R M} \Rightarrow  definition of midpoint

Step 2: The reflexive property of congruence states that a line segment or an angle or a shape is always equal to itself.  

\overline{P M} \cong \overline{P M} \Rightarrow Reflexive property of congruence.

Step 3: The SSS congruence postulate states that if three sides of a triangle are equal to three sides of another triangle, then the two triangles are congruent.

\Delta P Q M \cong \Delta P R M \Rightarrow  SSS congruence postulate

Step 4: CPCTC theorem states if two triangles are congruent then the sides and angles are also congruent.

\angle Q \cong \angle R \Rightarrow CPCTC theorem.

3 0
3 years ago
3. Problem 2: Suppose a radio manufacturer has the total cost function C (x) = 43x + $ 1850 and the revenue function R (x) = $ 8
OLEGan [10]

Given that,

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37x = 1850

x = 50

So, the required number of units are 50.

8 0
3 years ago
Use the diagram shown.
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

8 0
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Aleksandr [31]
\bf ~~~~~~ \stackrel{daily}{\textit{Continuously Compounding Interest Earned Amount}}\\\\&#10;A=Pe^{rt}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to& \$3150.37\\&#10;r=rate\to 4.1\%\to \frac{4.1}{100}\to &0.041\\&#10;t=years\to &20&#10;\end{cases}&#10;\\\\\\&#10;A=3150.37e^{0.041\cdot 20}\implies A=3150.37e^{0.82}\implies A\approx 7152.91457

how much interest is there?  well, A - 3150.37.
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3 years ago
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