In ΔQRS, the measure of ∠S=90°, QS = 60, RQ = 61, and SR = 11. What is the value of the sine of ∠R to the nearest hundredth?
2 answers:
Answer:
Sine R = opposite / hypotenuse
Sine R = 60 / 61 = .98360656
And we look up the arc sine of .98360656
and we find that Angle R = 79.611 Degrees
Step-by-step explanation:
Answer:
0.98
Step-by-step explanation:
sinR = opposite/hypotenuse
sinR = QS/QR
sinR = 60/61
sinR = 0.9836065574
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Answer:
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Step-by-step explanation:
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Answer:
B is your answer,
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