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3 years ago

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A box is filled with 2 brown cards,8 yellow cards, and 8 green cards. A card is chosen at random from the box. What is the proba

bility that the card is not yellow?

1 answer:

IgorLugansk [536]3 years ago

8 0

2 brown, 8 yellow, 8 green, thus our sample space is 2+8+8 = 18.

What is the probability that the card is NOT yellow? How many non-yellow are there? well 2 + 8 = 10, favorable outcomes.

$\bf \cfrac{\stackrel{\textit{favorable outcomes}}{10}}{\underset{\textit{sample space}}{18}}\implies \cfrac{5}{9}\implies 0.\overline{555}\qquad \approx \qquad 55.6\%$

You might be interested in

Rewrite the radical expression as an expression with a rational exponent. the seventh root of x to the third power

kherson [118]

The expression with a rational exponent of the seventh root of x to the third power is x to the three sevenths power ⇒ answer A

Step-by-step explanation:

Let us explain how to change the radical expression as an expression

with a rational exponent

1. Find the number of the root and make it the denominator of the

fraction exponent

2. Find the power of the term under the radical and make it the

numerator of the fraction exponent

Examples:

$\sqrt{x^{n}}=x^{\frac{n}{2}}$

$\sqrt[3]{x^{n}}=x^{\frac{n}{3}}$

$\sqrt[5]{x^{n}}=x^{\frac{n}{5}}$

So $\sqrt[m]{x^{n}}=x^{\frac{n}{m}}$

∵ the radical expression is the seventh root of x to the third power

∵ seventh root = $\sqrt[7]{}$

∵ x to the third power = x³

∴ seventh root of x to the third power = $\sqrt[7]{x^{3}}$

Let us change it to the rational exponent

∵ $\sqrt[m]{x^{n}}=x^{\frac{n}{m}}$

∵ $\sqrt[7]{x^{3}}$

∴ m = 7 and n = 3

∴ $\sqrt[7]{x^{3}}$ = $x^{\frac{3}{7}}$

∵ $x^{\frac{3}{7}}$ is x to the three sevenths power

∴ $\sqrt[7]{x^{3}}$ is x to the three sevenths power

The expression with a rational exponent of the seventh root of x to the third power is x to the three sevenths power

Learn more:

You can learn more about radical equation is brainly.com/question/7153188

#LearnwithBrainly

4 0

3 years ago

Read 2 more answers

A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w

AfilCa [17]

Answer:

$\frac{15}{4802}$ , $\frac{15}{9604}$ , $\frac{9}{2401}$ , $\frac{9}{4802}$

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: $\frac{4}{14}$

green: $\frac{2}{14}$

yellow: $\frac{3}{14}$

blue: $\frac{5}{14}$

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = $\frac{3}{14} \cdot \frac{4}{14} \cdot \frac{2}{14} \cdot \frac{5}{14} =\frac{15}{4802}$

Removing 1 blue, 1 green, 1 green, and 1 yellow = $\frac{5}{14} \cdot \frac{2}{14} \cdot \frac{2}{14} \cdot \frac{3}{14} =\frac{15}{9604}$

Removing 1 red, 1 red, 1 yellow, and 1 yellow = $\frac{4}{14} \cdot \frac{4}{14} \cdot \frac{3}{14} \cdot \frac{3}{14} =\frac{9}{2401}$

Removing 1 green, 1 yellow, 1 yellow, and 1 red = $\frac{2}{14} \cdot \frac{3}{14} \cdot \frac{3}{14} \cdot \frac{4}{14} =\frac{9}{4802}$

4 0

2 years ago

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 l

slamgirl [31]

Answer:

She will leave an extra video game which weighs 0.25lb

Step-by-step explanation:

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 lb), and a music player (0.4 lb). Using the inequality x ≤ 2.25, can she add all these items to the suitcase? If not, what could be left out to be closest to the maximum weight allowed?

Solution:

Weight of the items

hairdryer = 1.25 lb

hand-held video game = 0.6 lb

an extra video game = 0.25 lb music player = 0.4 lb

The total weight of the items

= 1.25lb + 0.25lb + 0.6lb + 0.4lb

= 2.5 lb.

Total weight - required weight

= 2.5lb - 2.25lb

= 0.25lb

2.5lb is 0.25lb greater than 2.25lb

Therefore, not all items can be added.

She has to leave out an item equivalent to 0.25lb

Item equivalent to 0.25lb is the extra video game

If Li leaves out the extra game, which weighs 0.25 lb, she’d have the maximum weight allowed.

5 0

3 years ago

MATH QUESTION SCREEN SHOT DOWN BELOW

Lisa [10]

F(x)= (x-p)²+q where (p,q) is min point
f(x)=(x-1)²-2
min point is (1,-2)
the answer is first picture

8 0

2 years ago

The following are questions from a self-quiz.According to some study, the height for Northern European adult males is normally d

lara [203]

Answer:

a) 0.064

b) 0.109

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 181 centimeter

Standard Deviation, σ = 7.3 centimeter

We are given that the distribution of height for Northern European adult males is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(person is between 160 and 170 centimeters)

$P(160 \leq x \leq 170) = P(\displaystyle\frac{160 - 181}{7.3} \leq z \leq \displaystyle\frac{170-181}{7.3}) = P(-2.8767 \leq z \leq -1.506)\\\\= P(z \leq -1.506) - P(z < -2.8767)\\= 0.066 -0.002 = 0.064 = 6.4\%$

b) P(person is higher than 190 centimeter)

P(x > 190)

$P( x > 190) = P( z > \displaystyle\frac{190 - 181}{7.3}) = P(z > 1.2328)$

$= 1 - P(z \leq 1.2328)$

Calculation the value from standard normal z table, we have,

$P(x > 190) = 1 - 0.891 = 0.109 = 10.9\%$

7 0

3 years ago