Answer:
a. They would have half chromosomes as much as the plants body cells.
b. Meiosis
Explanation:
Gametes are sex cells produced only in sexually reproducing organisms. In plants as stated in this question, male gametes are contained in pollens while female gametes are contained in ovules. The process by which these gametes are made is called MEIOSIS.
Meiosis is a cell division that reduces the chromosomal number of the parent cell by half. This means that each GAMETE will contain half the number of chromosomes as the parent cell. Fir example, if the body cell of a plant contains 30 chromosomes, each gamete formed via Meiosis in that plant will have 15 chromosomes.
In a nutshell, pollen and ovules, which are gametes of plants formed by MEIOSIS would have half chromosomes as much as the plants body cells.
Which information would<span> be </span>appropriate<span> for the </span>nurse<span> to include in the teaching plan ... Which </span>term should<span> the </span>nurse use<span> to </span>describe<span> the serous membrane covering .... </span>describe<span> a </span>client<span> who </span>has<span> a </span>positive tuberculin skin test but<span> is </span>asymptomatic. And <span>Indeterminate isn't a </span>term used<span> to </span>describe<span> results of a </span>PD test<span>. If the </span>PD<span> is ... </span>positive. However, all but<span> infants and suppressed people will remain </span>asymptomatic<span>. ... A </span>client<span> with a </span>positive skin test<span> for </span>TB<span> isn't showing signs of active disease. .... The </span>nurse correctly<span> interprets this reaction to mean that the </span>client has<span>:</span>
The answer will be C) Electrons and Ions love
First, write out all combinations for the parents:
<u>SsBB</u>:
SB
sB
SB
sB
<u>ssBb</u>:
sB
sb
sB
sb
So now that you know what to put on as the x and y for the Punnett Square, set it up:
<u> | SB | sB | SB | sB </u>
<u>sB | SsBB | ssBB | SsBB | ssBB </u>
<u>sb | SsBb | ssBb | SsBb | ssBb </u>
<u>sB | SsBB | ssBB | SsBB | ssBB </u>
<u>sb | SsBb | ssBb | SsBb | ssBb </u>
Now, listing each possible genotype and the number of times they show up in the square:
SSBB
0 times
SSBb/SSbB
0 times
SSbb
0 times
SsBB/sSBB
4 times
SsBb/SsbB/sSBb/sSbB/
4 times
Ssbb/sSbb
0 times
ssBB
4 times
ssBb/ssbB
4 times
ssbb
0 times
Since there are only 4 genotypes are possible, set up ratios of those four:
SsBB:
4 times/16 total = .25 = 25%
SsBb:
4 times/16 total = .25 = 25%
ssBB:
4 times/16 total = .25 = 25%
ssBb:
4 times/16 total = .25 = 25%
This means that the<em> genotypes</em> have a 25% : 25% : 25% : 25% likelihood.
Now, let's figure out the phenotypes of the 4 genotypes:
SsBB:
Ss = dominant
BB = dominant
SsBb:
Ss = dominant
BB = dominant
ssBB:
ss = recessive
BB = dominant
ssBb:
ss = recessive
Bb = dominant
So we have 2/4 that are S-dominant B-dominant and 2/4 that are S-recessive B-dominant.
This means that the phenotypes are:
2/4 = 50% Thin stripes with black eyes, and
2/4 = 50% Thin stripes with gray eyes.
I hope this helped you out :)
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