Now, listing each possible genotype and the number of times they show up in the square: SSBB 0 times SSBb/SSbB 0 times SSbb 0 times SsBB/sSBB 4 times SsBb/SsbB/sSBb/sSbB/ 4 times Ssbb/sSbb 0 times ssBB 4 times ssBb/ssbB 4 times ssbb 0 times
Since there are only 4 genotypes are possible, set up ratios of those four:
SsBB: 4 times/16 total = .25 = 25%
SsBb: 4 times/16 total = .25 = 25%
ssBB: 4 times/16 total = .25 = 25%
ssBb: 4 times/16 total = .25 = 25%
This means that the<em> genotypes</em> have a 25% : 25% : 25% : 25% likelihood.
Now, let's figure out the phenotypes of the 4 genotypes: SsBB: Ss = dominant BB = dominant
SsBb: Ss = dominant BB = dominant
ssBB: ss = recessive BB = dominant
ssBb: ss = recessive Bb = dominant
So we have 2/4 that are S-dominant B-dominant and 2/4 that are S-recessive B-dominant. This means that the phenotypes are: 2/4 = 50% Thin stripes with black eyes, and 2/4 = 50% Thin stripes with gray eyes.