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UNO [17]
3 years ago
10

Jay is measuring the sides and angles of a number of triangles looking for a triangle that is congruent to triangle XYZ below wh

ich set of side light has could come from a congruent triangle

Mathematics
1 answer:
sergey [27]3 years ago
7 0

Answer:

correct answer is B.

Step-by-step explanation:

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Separate the number 219 into three parts. The second number is two less than 5 times the first number, and the third number is 4
Sav [38]
Let us assume the first number = x
Then the second number = 5x -2
The third number = x + 4
The total number that needs to be divided into three parts is 219
Then we can write the equation as
x + 5x - 2 + x + 4 = 219
7x + 2 = 219
7x = 219 - 2
7x = 217
x = 217/7
  = 31
Then
First number = 31
Second number = 5x - 2
                           = (5 * 31) - 2
                           = 155 -2
                          = 153
Third number = x + 4
                       = 31 + 4
                       = 35
So the three numbers are 31, 153 and 35.
4 0
3 years ago
Match the reasons with the statements in the proof to prove DF = EF, given that DEF is a triangle by definition and angles 3 and
icang [17]

Answer with explanation:

Given:

In Δ DEF, ∠3=∠4.

To prove:→ DE=E F

Proof:

1.  ∠3=∠4------[Given]

2. →∠1 and ∠ 3 are Supplementary to each other.

(a)⇒∠1 + ∠ 3=180°

 →∠2 and ∠ 4 are also Supplementary to each other.

(b)⇒∠2 + ∠ 4=180°

                                     --------------------[Exterior sides in opposite rays]

3. From 1 , a and b

 ⇒∠ 1 = ∠ 2-------[Two Angles Supplementary to equal Angles are equal to each other]

4. \Bar{DE}=\Bar{E F}

 If two angles of a Triangle are equal , then side opposite to these angles are equal.

6 0
4 years ago
Strontium-90 has a half-life of 28.8 years. If you start with a 300-gram sample of strontium-90,
Kazeer [188]

Answer:  2.66 × 10⁻¹³

<u>Step-by-step explanation:</u>

First, use the decay formula   A=A_oe^{kt}   where

  • A is the final amount (amount left)
  • A₀ is the initial amount (amount you started with)
  • k is the rate of decay (you need to solve for this)
  • t is the time

Given:

  • A = 1/2(300) = 150
  • A₀ = 300
  • k = unknown
  • t = 28.8

150=300e^{28.8k}\\\\0.5=e^{28.8k}\\\\ln(0.5)=ln(e^{28.8k})\\\\ln(0.5)=28.8k\\\\\\\dfrac{ln(0.5)}{28.8}=k\\\\\\\large\boxed{-0.0240676=k}\\

Next, input the k-value and the new t-value to solve for A.

  • A = unknown
  • A₀ = 300
  • k = -0.0240676
  • t = 1440

A=300e^{1440(-.0240676)}\\\\\large\boxed{A=2.66\times 10^{-13}}\\

5 0
4 years ago
Can you help with this please I have to go
vagabundo [1.1K]
1) a
2)b
3)d
4)c
5)a

I hope this helped you!!
3 0
3 years ago
F(x)=(−x−2)(−2x−3) find the first solution and then the second
harina [27]

X=-2, -3/2

_(-2)-2=0

-2(-3/2)-3=0

5 0
4 years ago
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